P(odd) or P(multiple of 5)
When we roll 2 number cubes
all possible outcomes of their sum are 2,3,4,5,6,7,8,9,10,11,12.(11 possible outcomes)
Out of those possible outcomes
3,5,7,9,11 are odd (5 outcomes) and ...
5 and 10 are multiples of 5 (2 outcomes)
Now, P(odd) or P(multiple of 5) really means P(odd) + P (multiple of 5) =
(If we had “and” instead of “or” we multiply)
= (5/11) +(2/11)
=7/11
Answer: %0.00100010001
Step-by-step explanation:
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
(x - 3)² + (y + 9)² = 25
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
Given area = 25π , that is
πr² = 25π ( divide both sides by π )
r² = 25 ( take the square root of both sides )
r = 
= 5
With centre (h, k) = (3, - 9 ) and r = 5 , then
(x - 3)² + (y - (- 9) )² = 5² , that is
(x - 3)² + (y + 9)² = 25
Answer:
jvhhhhchgcgvvv
Step-by-step explanation:
