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Rzqust [24]
2 years ago
10

Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.

Mathematics
1 answer:
natta225 [31]2 years ago
4 0

Step-by-step explanation:

(2, 4)

(2, 1)

(6, 12)

(4, -5)

(-2, 4)

(2, -4)

(6, -12)

(-4, 5)

Quadrilateral ABCD is reflected over the x-axis.

arrowRight

Quadrilateral ABCD is translated 2 units right and 1 unit down.

arrowRight

Quadrilateral ABCD is dilated about the origin by a scale factor of 3.

arrowRight

Quadrilateral ABCD is rotated 180° clockwise about the origin.

arrowRight

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30 yd wide and 50 yd long find the length of the diagonal
Troyanec [42]
It's the same as finding the hypothenuse of a right triangle. Let c be the hypothenuse.

30 squared+ 50 squared= c squared.

900+ 2500= c squared
3400= c squared

Then find the square root of 3400 and that will equal c.

So, depending in what form the teacher was the answer. The answer will be square root of 3400 ft squared or 58.3 ft squared.
8 0
3 years ago
17) List the ways five dogs a Beagle, a Collie, a Greyhound, a Poodle and a
Gnoma [55]

Answer:

  • <u>10 pairs</u>
  • <u>It is a combination</u>

<u></u>

Explanation:

This is a combination because the order does not matter: the Beagle - Collie couple is the same as the Collie - Beagle couple, so it is only counted once.

The formula for combinations is:

           C(m,n)=\dfrac{m!}{n!\cdot (m-n)!}

For five diffferent dogs to be put in pairs, the number of different pairs is:

         C(5,2)=\dfrac{5!}{2!\cdot (5-2)!}=\dfrac{5\times 4}{2}=10

4 0
3 years ago
The proof shows that opposite angles of a parallelogram are congruent. Given: ABCD is a parallelogram with diagonal AC. Prove: ∠
Rom4ik [11]

A parallelogram is a figure which has its <em>opposite</em> sides to be <u>equal</u> and <u>parallel</u>. The <em>missing</em> reason in the proof is:

B. Substitution Angle Angle Postulate.

A <em>parallelogram</em> is a type of quadrilateral that has its <u>opposite</u> sides to be equal and parallel. The sum of its <em>internal</em> angles is 360^{o}.

To <u>prove</u> that ∠ BAD ≅ ∠ DCB, we have:

Given parallelogram ABCD;

<BAC ≅ <ACD (alternate angle theorem)

<DAC ≅ <ACB (alternate angle theorem)

<BAC + <DAC = <BAD

Also,

<BCA + <DCA = <BCD

Therefore,

<BAD ≅ <DCB (Substitution Angle Angle Postulate)

Thus, the <u>missing</u> reason in the partial proof is:

option B. Substitution Angle Angle Postulate

A sketch is attached to this question for more clarifications.

Visit: brainly.com/question/3100335

4 0
2 years ago
In a recent survey of students who graduated from a large public high school, nine out of ten students reported that they passed
vladimir2022 [97]
A review of the students’ school transcripts
4 0
3 years ago
Simplify (7x+42)/(x^2+13x+42)
Colt1911 [192]
\frac{7x+42}{x^2+13x+42}=  \frac{7(x+6)}{x^2+7x+6x+42}=   \frac{7(x+6)}{x(x+7)+6(x+7)}=  \frac{7(x+6)}{(x+6)(x+7)}=  \frac{7}{x+7}
7 0
3 years ago
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