All categories

3 years ago

What is the average of 1.90 7.99 4.33 5.21?

2 answers:

7 0

Add All The Numbers (Which Gives You 19.43) Then Divide By Four Because There Are Four Numbers That Were Added Together. The Average Is 4.8575.

Strike441 [17]3 years ago

6 0

The average is 4.8575

You might be interested in

Marissa bought 60 horns for her New Year’s Eve party for $83.40.

anzhelika [568]

That would cost her $25.02

Unsure what the T/F statements are they are not included

7 0

3 years ago

33) Name four congruent angles that are obtuse angles.

Gnom [1K]

1,4,5,8 i think try tgat

6 0

3 years ago

Jamie is riding a Ferris wheel that takes fifteen seconds for each complete revolution. The diameter of the wheel is 10 meters a

Agata [3.3K]

Answer:

The answers to the question is

(a) Jamie is gaining altitude at 1.676 m/s

(b) Jamie rising most rapidly at t = 15 s

At a rate of 2.094 m/s.

Step-by-step explanation:

(a) The time to make one complete revolution = period T = 15 seconds

Here will be required to develop the periodic motion equation thus

One complete revolution = 2π,

therefore the we have T = 2π/k = 15

Therefore k = 2π/15

The diameter = radius of the wheel = (diameter of wheel)/2 = 5

also we note that the center of the wheel is 6 m above ground

We write our equation in the form

y = $5*sin(\frac{2*\pi*t}{15} )+6$

When Jamie is 9 meters above the ground and rising we have

9 = $5*sin(\frac{2*\pi*t}{15} )+6$ or 3/5 = $sin(\frac{2*\pi*t}{15} )$ = 0.6

which gives sin⁻¹(0.6) = 0.643 = $\frac{2*\pi*t}{15}$

from where t = 1.536 s

Therefore Jamie is gaining altitude at

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ 1.676 m/s.

(b) Jamie is rising most rapidly when the velocity curve is at the highest point, that is where the slope is zero

Therefore we differentiate the equation for the velocity again to get

$\frac{d^2y}{dx^2} = -5*(\frac{\pi *2}{15} )^2*sin(\frac{2\pi t}{15})$ =0, π, 2π

Therefore $-sin(\frac{2\pi t}{15} )$ = 0 whereby t = 0 or

$\frac{2\pi t}{15}$ = π and t = 7.5 s, at 2·π t = 15 s

Plugging the value of t into the velocity equation we have

$\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi t}{15}) =$ - 2/3π m/s which is decreasing

so we try at t = 15 s and we have $\frac{dy}{dt} = 5*\frac{\pi *2}{15} *cos(\frac{2\pi *15}{15}) = \frac{2}{3} \pi$ m/s

Hence Jamie is rising most rapidly at t = 15 s

The maximum rate of Jamie's rise is 2/3π m/s or 2.094 m/s.

7 0

3 years ago

in the diagram, a building casts a 35-ft shadow and a flagpole casts a 10-ft shadow. if the flagpole is 22tall, how tall is the

8_murik_8 [283]

Let, the height of the building be x ft.

Given the building casts 35ft shadow.

The height of the flagpole given which is 22ft and casts a shadow of 10ft.

Now to find the height of the building we have to equate the ratio of height and shadow of the building and the flagpole.

So we can write,

x/35 = 22/10

To find x, we have to get rid of 35 from the left side and have to move it to right side. As 35 is divided there, we will multiply 35 to both sides.

(x/35)× 35 = (22/10)×35

x = (22×35)/10

x = 770/10

x = 77

So, the height of the building is 77 ft which is the required answer here.

8 0

3 years ago

If I live 16 minutes away from a movie theater and I need to be there at 5 what time do I leave

TEA [102]

Answer:

4:44 so that you could be there at 5:00 exactly.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers