All categories

3 years ago

Match the equation with its corresponding solution for x.

Mathematics

1 answer:

Fudgin [204]3 years ago

4 0

To solve for x, you need to isolate/get the variable "x" by itself in the equation:

3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)

3x + (-3)x + (-3)1 = 3

3x - 3x + 1 = 3

1 = 3

Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3

You might be interested in

PLEAE HELP WILL GIVE YOU BRAINLIEST. Simplify 3<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="

gladu [14]

18sqrt(x)
I'm assuming that 3(sqrt(x))5 is equal to 15sqrt(x). If that is the case, just perform the multiplication within each term and treat the sqrt(x) as a variable when you add the all together. It is okay because they are like terms.

7 0

3 years ago

A voter polling research group determined that 41% of the voters in a country would vote for the democratic candidate with a 4%

Soloha48 [4]

Answer:b will be the answer

Step-by-step explanatio

8 0

2 years ago

Read 2 more answers

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

3 years ago

19. What is the equation of the line in slope-intercept form that passes through the point (24,9) and 1/8

Y_Kistochka [10]

Answer:

y=1/8x+6

Step-by-step explanation:

y-y1=m(x-x1)

y-9=1/8(x-24)

y=1/8x-24/8+9

y=1/8x-3+9

y=1/8x+6

6 0

3 years ago

Is tu parallel to vw? Explain.

Varvara68 [4.7K]

Answer: C

Step-by-step explanation:

6 0

2 years ago