Answer:
1 ≤ n
Step-by-step explanation:
7−3n ≤ n+3
+3n +3n
7 ≤ 4n+3
-3 -3
4 ≤ 4n
divide by 4 on each side
1 ≤ n
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Answer:
a(n) = 20*2.5^(n - 1)
Step-by-step explanation:
Note that 50 is 2.5 times 20, and that 125 is 2.5 times 50. Thus the common factor is 2.5. The formula for the nth term is
a(n) = a(1)*r^(n - 1) => a(n) = 20*2.5^(n - 1)
Answer
A: (1,7.5)
b:(0,6)
c: because the graph is linear graph and have a constant rate of change/ slope which is -1.5
Step-by-step explanation:
Answer:
B. r + l = 45; 2r + 3l = 96
39 regular; 6 long-distance
Step-by-step explanation:
There were 45 baskets, so
(1) r + l = 45
There were 96 points in the game, so
(2) 2r + 3l = 96
Solve equation (1) for l
l = 45 – r Substitute the value for l in Equation (2)
2r + 3(45 – r) = 96 Remove parentheses
2r + 135 - 3r = 96 Combine like terms
-r + 135 = 96 Subtract 135 from each side
-r = -39 Multiply each side by -1
r = 39 Substitute the value of r in Equation (1)
39 + l = 45 Subtract 39 from each side
l = 6
===============
Check:
(1) 39 + 6 = 45
45 = 45
(2) 2×39 + 3×6 = 96
78 + 18 = 96
96 = 96
