A mother gives birth to a 9 pound baby. every 4 months, the baby gained 2 pounds. if x is the age of the baby in months, then y
1 answer:
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Answer: The statements in options 2 and 4 are true.
Explanation:
The LCM of two numbers is the smallest number that is multiple of both numbers.
The factor of 8 and 12 are,
Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,
Therefore the statement in option 1 is incorrect.
The factor of 6 and 9 are,
Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,
Therefore the statement in option 2 is correct.
The factor of 11 and 4 are,
Since all factor are different, therefore the L.C.M. of 11 and 4 is,
Therefore the statement in option 3 is incorrect.
The factor of 9 and 10 are,
Since all factor are different, therefore the L.C.M. of 9 and 10 is,
Therefore the statement in option 4 is correct.
The rocks are chosen without replacement, which means that the hypergeometric distribution is used to solve this question. First we get the parameters, and then we answer the questions. From this, we get that:
- P(X < 6) = 0.9545
- P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
The mean and the variance are:
We have that:
5 + 7 = 12 rocks, which means that
9 are chosen, which means that
7 are granite, which means that
Question a:
Thus:
Question b:
Since there are only 5 specimens of basaltic rock, at least 9 - 5 = 4 specimens of granite are needed, which means that:
In which
Thus
So P(X < 6) = 0.9545.
Question c:
5 of basaltic and 4 of granite: 0.1591 probability.
7 of granite is P(X = 7), in which
0.1591 + 0.0455 = 0.2046, thus:
P(all specimens of one of the two types of rock are selected for analysis) = 0.2046.
A similar question is found at brainly.com/question/24008577