Answer:
18.88% probability that three or four customers will arrive during the next 30 minutes
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Average rate of 6.4 per 30 minutes.
This means that 
What is the probability that three or four customers will arrive during the next 30 minutes?
18.88% probability that three or four customers will arrive during the next 30 minutes
Answer:
0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car
Step-by-step explanation:
Given :The chance of winning a car is 1 in 1,000.
To Find : What percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car?
Solution:
The chance of winning a car is 1 in 1,000.
The percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car:
=
=
=
Hence 0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car.
Answer:
answer is the first one
Step-by-step explanation:
i dont know how to explain it
The correct answer would be True zorreos can be significant digits.
Answer:
110011
Step-by-step explanation:
The tedious way to do this is to divide by 2 until the quotient is 0, noting remainders at each step:
- 51/2 = 25 r 1
- 25/2 = 12 r 1
- 12/2 = 6 r 0
- 6/2 = 3 r 0
- 3/2 = 1 r 1
- 1/2 = 0 r 1
Taken from bottom to top, the list of remainders comprises the binary number: 110011.
___
Alternatively, you can convert the number to hexadecimal (base-16) or octal (base-8), then make the simple conversions from those digits to binary. In octal, we have ...
Then the number in octal is 51 = 63₈. Your familiarity with binary lets you write the binary number from memory, since you recall 6 = 110₂ and 3 = 011₂. Each octal digit must be expressed as three binary digits (or bits) in order to maintain appropriate place values.
That is, ...
63₈ = 110011₂
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<em>Comment on octal-binary conversion</em>
The binary values of the digits 0-7 are ...
- 0 = 000₂
- 1 = 001₂
- 2 = 010₂
- 3 = 011₂
- 4 = 110₂
- 5 = 101₂
- 6 = 110₂
- 7 = 111₂
Three binary bits can express numbers 0-7 as shown. So, using octal as an intermediate base in doing the conversion to binary lets you do the conversion 3 bits at a time, instead of one bit at a time.
Likewise, four binary bits can express numbers 0-15, so hexadecimal as an intermediate base lets you do the conversion 4 bits at a time: 51/16 = 3 r 3 ⇒ 0011 0011₂.
