Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
The answer is c ................
Answer:
11 feet
Step-by-step explanation:
Squares have the same length and width. So you just take the square root of teh area to find both.
√121 = 11
Answer:
Step-by-step explanation:
Your "y=2xsquared-12x+10" translates into y = 2x^2 - 12x + 10. This factors into y = 2(x^2 - 6x + 5).
Setting this = to 0 results in y = 2(x - 5)(x - 1) = 0, so that the x-intercepts are (5, 0) and (1, 0). The x-coordinate of the vertex lies halfway between x = 1 and x = 5, that is, at x = 3. Using synthetic division to evaluate y = 2x^2 - 12x + 10 at x = 3, we get
3 2 -12 10
6 -18
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2 -6 -8
Therefore, the vertex is located at (3, -8).
Setting x = 0 results in the y-intercept: y = 2(0)^2 - 12(0) + 10 => (0, 10)
