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8_murik_8 [283]
2 years ago
9

In ACME PUBLISHING SWEEPSTAKES, the chance of winning a car is 1 in 1,000. What percent of tickets to ACME PUBLISHING SWEEPSTAKE

S win a car?
Mathematics
1 answer:
Yuri [45]2 years ago
8 0

Answer:

0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car

Step-by-step explanation:

Given :The chance of winning a car is 1 in 1,000.

To Find : What percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car?

Solution:

The chance of winning a car is 1 in 1,000.

The percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car:

=\frac{1}{1000} \times 100

=\frac{1}{10}

=0.1\%

Hence 0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car.

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ABCD is a parallelogram. Find the values of x and y. Solve for the value of z, if z=x−y.
slava [35]

Answer:

C

Step-by-step explanation:

Parallel and opposite sides of a parallelogram are equal. Hence, we can say:

x + 30 = 2x - 10

and

2y-10 = y +10

Solving first one, we get:

x + 30 = 2x - 10

30+10 = x

x = 40

Also

2y - 10 = y + 10

y = 10 + 10

y = 20

Now, z = x - y, so

z = 40 - 20 = 20

Answer C is right.

3 0
3 years ago
What are 3 different quotients that equal 4 to the negative 5th power
Ilia_Sergeevich [38]
4^-5=1/1024 or 2/2048 or 3/3072
8 0
3 years ago
A tepee is designed to have a diameter of 10 ft and a volume of 393 ft. At
Citrus2011 [14]

Answer:

15 ft.

Step-by-step explanation:

The tepee is a cone and its volume

= 1/3 pi r^2 h   where r = radius and h = height.

The radius r = 1/2 * 10 = 5 ft.

So we have the equation:

393 = 1/3*3.14* 5^2 * h

h = 393 / (1/3*3.14*25)

=  15.02 ft.

7 0
3 years ago
Find the 12th term of the following geometric sequence.<br> 3, 12, 48, 192
zavuch27 [327]
12th term is 12,582,912
6 0
3 years ago
Find the first five terms of the recursive sequence <br> an=-6an-1 where a1=4.5
grandymaker [24]

Answer:

4.5, -27, 162,-972, 5832

Step-by-step explanation:

The given recursive definition is,

a_n=-6a_{n-1}, a_1=4.5

This will form a geometric sequence with first term 4.5 and common ratio r=-6.

When n=2, we have:

a_2=-6a_1 \\  \implies \: a_2=-6 \times 4.5 =  - 27

When n=3, we get:

a_3=-6a_2 \\  \implies \: a_3=-6 \times  - 27 =  162

When n=4, we get:

a_4=-6a_3 \\  \implies \: a_4=-6 \times 162 =  - 972

When n=5, we get:

a_5=-6a_4 \\  \implies \: a_5=-6 \times  - 972 = 5832

Therefore the first five terms are:

4.5, -27, 162,-972, 5832

3 0
3 years ago
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