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3 years ago

There is one real solution if the radicand is

Mathematics

1 answer:

kumpel [21]3 years ago

4 0

Here I have attached a photo to help you with this:

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Find the value when x= 2 and y= 3.<br> x^-3y^-3

Bas_tet [7]

Answer:

1/216

Step-by-step explanation:

x^(-3)y^(-3)

(2)^(-3)=1/2^3=1/8

(3)^(-3)=1/3^3=1/27

(1/8)(1/27)=1/216

4 0

3 years ago

A movers ramp is placed on top

Salsk061 [2.6K]

Answer:

I think it would be 13 feet

Step-by-step explanation:

12*5=60

and sense it is a triangle you divide by 2 and get 30

<h3>30-12-5=13</h3><h3>this is what I think</h3>

4 0

3 years ago

HELP ASAP!!!! There is a clip below.

Len [333]

Answer:

eqn : 9 x 9 x h = 1620

h = 1620 / 81 = 20

Step-by-step explanation:

7 0

2 years ago

The radius of a circle is 7 inches. What is the area?

Basile [38]

Answer:

21.98

Step-by-step explanation:

7*3.16=21.98

3 0

3 years ago

Read 2 more answers

What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

4 0

3 years ago

Read 2 more answers