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arsen [322]
3 years ago
7

Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t

he length of the third side be). Write the inequalities for each case.
13.2 and 6.7
Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

 c^{2} =a^{2}+b^{2}+2abcos\alpha---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and \alpha is the angle between a and b .

In equation 1 , the maximum and minimum values of cos\alpha are 1 and -1.

 so the value of c  lies in between

⇒ \sqrt{a^{2}+b^{2}-2ab   } and  \sqrt{a^{2}+b^{2}+2ab  }   = |a-b| and |a+b|

Given a=13.2 and b=6.7 so the the side lies in between  |13.2-6.7| and |13.2+6.7|

  so the third side lies between 6.5 and 19.9

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Answer:

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Step-by-step explanation:

y=3x-7

x=0 ⇒ y= 3*0-7= -7

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I am a 2 dimensional shape that had 5 obtuse angles
Montano1993 [528]

Answer:

A pentagon.

Step-by-step explanation:

A pentagon is a 5-sided polygon. Its interior angles each are equivalent to 108°.

108° ≥ 90°,  so the angles are obtuse.

Therefore, a 2-D shape with 5 obtuse angles is a <u>pentagon</u>.

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The quotient of the sum of r and s spilt into 3 equal groups
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(r+s)÷3

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4 0
3 years ago
12
nikitadnepr [17]

Considering the given discrete probability distribution, it is found that the expected share is of 10%.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

In this problem, the distribution is given by:

  • P(X = 0.05) = 0.2.
  • P(X = 0.1) = 0.6.
  • P(X = 0.15) = 0.2.

Hence the expected value is given by:

E(X) = 0.2 x 0.05 + 0.6 x 0.1 + 0.2 x 0.15 = 0.1 = 10%.

The expected share is of 10%.

More can be learned about the expected value of a discrete distribution at  brainly.com/question/24802582

#SPJ1

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