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arsen [322]
3 years ago
7

Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t

he length of the third side be). Write the inequalities for each case.
13.2 and 6.7
Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

The length of the third side of given triangle lies between 6.5 and 19.9.

Step-by-step explanation:

The law of cosine is as follows

 c^{2} =a^{2}+b^{2}+2abcos\alpha---------------1

⇒ a and b are the given sides of the triangle and c is the third side, and \alpha is the angle between a and b .

In equation 1 , the maximum and minimum values of cos\alpha are 1 and -1.

 so the value of c  lies in between

⇒ \sqrt{a^{2}+b^{2}-2ab   } and  \sqrt{a^{2}+b^{2}+2ab  }   = |a-b| and |a+b|

Given a=13.2 and b=6.7 so the the side lies in between  |13.2-6.7| and |13.2+6.7|

  so the third side lies between 6.5 and 19.9

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Step-by-step explanation:

     9         8       1

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The question is asking for to round to the nearest hundred (100) which means is rounding to [9] in this question.

The number of the place before the hundreds place is [8] on the tens place.

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