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Andru [333]
2 years ago
13

Debbie is borrowing 3 books from her friend who has a collection of 45 books. Which of the following expressions represents the

number of ways Debbie can choose a group of 3 books?
a.P(45, 3)
b.C(45, 3)
b.45!
Mathematics
2 answers:
choli [55]2 years ago
6 0
The order of the 3 books does not matter  so its the number of combinations of 3 from 45 

b is the correct choice
olya-2409 [2.1K]2 years ago
5 0

Answer: b.C(45, 3)

Step-by-step explanation:

Given: Debbie is borrowing 3 books from her friend who has a collection of 45 books.

Therefore,  the number of ways Debbie can choose a group of 3 books will be equal to the number of combinations of selecting 3 books from 45 books.

i.e. The number of ways Debbie can choose a group of 3 books=C(45, 3)

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Point S is your answer.

Step-by-step explanation:

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Point S is your answer.

6 0
2 years ago
Read 2 more answers
c) The GCF and LCM of two numbers are 2 and 70 respectively. If one of the numbers is 10, find the other number? [3m] solution:
Mice21 [21]

Their LCM is

70

hope it helps you.

8 0
2 years ago
The sticker has a base of 6.5cm and a height of 10.1. What is the area of the sticker?
coldgirl [10]

Answer:

65.65

Step-by-step explanation:

1) Carry over the decimals in each number.

2) Multiply. This will give you 6,565.

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4 0
2 years ago
Jane brought x shirts for $20 each and y skirts for $25 each she spent $210 in all. which equation represents this situation 2
miv72 [106K]

Answer:

Part A

20x + 25y = 210 --> D.

Part B

If jane purchased exactly 4 shirts she must have purchased Exactly ___ skirts. (round to the nearest tenth)

20*4 + 25y = 210 --> y = 5.2

is it possible for jane to purchase exactly 4 shirts? ____(yes or no)

no, because she can't buy 5.2 skirts.

5 0
3 years ago
Read 2 more answers
Which of the following best describes the
ehidna [41]
k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}

Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel


Answer:\boxed{C-The\ lines\ intersect\ but\ are\ not\ perpendicular.}
3 0
3 years ago
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