Step-by-step explanation:
<h3>Let the number be x </h3><h3>X×5 =1/2 × 3/5 × 61</h3><h3>5X = 18 </h3><h3>X = 18/5 </h3><h3>X =3.3</h3>
(a) 2x + 5x + 4 = 25 <== ur equation
7x + 4 = 25
7x = 25 - 4
7x = 21
x = 21/7
x = 3
(b) first piece = 2x....= 2(3) = 6 ft <=
second piece = 5x....= 5(3) = 15 ft <=
Answer:
see below
Step-by-step explanation:
All of the given data sets have x-values that are sequential with a difference of 1. That makes it easy to determine the sort of sequence the y-values make.
<u>first choice</u>: the y-values have a common difference of -2. This will be matched by a linear model.
<u>second choice</u>: the y-values have a common difference of +2. Again, this will be matched by a linear model.
<u>third choice</u>: the y-values have a common ratio of -2. This will be matched by an exponential model.
<u>fourth choice</u>: the y-value differences are 3, 5, 7, increasing by a constant amount (2). This is characteristic of a sequence that has a quadratic model.
Answer:
Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)
The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.
Step-by-step explanation:
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The third one is the answer
