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3 years ago

Help if you can with all answers or at least some

Mathematics

2 answers:

yan [13]3 years ago

7 0

Area of a circle is pi * radius² so:

1) Area = pi * 5²

= 25pi ≈ 78.54 yd²

2) Area = pi * 7²

= 49pi ≈ 153.94 cm²

Circumference is 2 * pi * radius so:

3) Circumference = 2 * pi * 10

= 20pi ≈ 62.83 mi

4) Circumference = 2 * pi * 3.3

= 6.6pi ≈ 20.73 in

Volume of a rectangular prism is length * width * height

5) Volume = 10 * 3 * 10

= 100 * 3
= 300 yd³

6) Volume = 5 * 7 * 5

= 35 * 5
= 175 in³

Not completely sure on the triangular prisms though. I'm almost certain the formula is 1/2 * height * base 1 * base 2 though

trasher [3.6K]3 years ago

6 0

1). You use the formula A=(pi)r^2
A=(pi)(5)^2
A= 78.5yd

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Step-by-step explanation:

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2 years ago

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Keith_Richards [23]

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% slope = m
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3 years ago

Determine if the events A and B are independent. Show all steps.

zmey [24]

Answer:

$P(A U B ) = \frac{13}{25}$

Step-by-step explanation:

STEP:-1

Given that events A and B are independent then

P(A ∩B ) = P(A) P(B)

Given that P(A) = 2/5 and P(B) = 1/5

STEP:- 2

P(A ∩B ) = P(A) P(B)

$P(A U B) = P(A) +P(B) - P(A n B )$

$P(A U B ) = P(A) +P(B) - P(A) P(B)$

Step(iii):-

$P(A U B ) = \frac{2}{5} +\frac{1}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{5} X \frac{1}{5}$

$P(A U B ) = \frac{3}{5} - \frac{2}{25}$

$P(A U B ) = \frac{15-2}{25} = \frac{13}{25}$

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2 years ago

What is the andwer???

djverab [1.8K]

Answer:

3 and 11

Step-by-step explanation:

Given 2 sides with third side x , then

difference of 2 sides < x < sum of 2 sides , that is

7 - 4 < x < 7 + 4

3 < x < 11

Thus the possible values the third side cannot be are 3 and 11

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2 years ago

Let f ( ) sin(arctan ) x x = . What is the range of f ?

nikklg [1K]

So you have composed two functions,
h(x)=sin(x) and g(x)=arctan(x)
→f=h∘g
meaning
f(x)=h(g(x))
g:R→[−1;1]
h:R→[−π2;π2]
And since
[−1;1]∈R→f is defined ∀x∈R

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]
Meaning
f:R→[arctan(−1);arctan(1)]=[−π4;π4]
so there's your domain

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2 years ago