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mart [117]
3 years ago
11

Help if you can with all answers or at least some

Mathematics
2 answers:
yan [13]3 years ago
7 0
Area of a circle is pi * radius² so:

1) Area = pi * 5²

= 25pi ≈ 78.54 yd²

2) Area = pi * 7²

= 49pi ≈ 153.94 cm²

Circumference is 2 * pi * radius so:

3) Circumference = 2 * pi * 10

= 20pi ≈ 62.83 mi

4) Circumference = 2 * pi * 3.3

= 6.6pi ≈ 20.73 in

Volume of a rectangular prism is length * width * height

5) Volume = 10 * 3 * 10

= 100 * 3
= 300 yd³

6) Volume = 5 * 7 * 5

= 35 * 5
= 175 in³

Not completely sure on the triangular prisms though. I'm almost certain the formula is 1/2 * height * base 1 * base 2 though
trasher [3.6K]3 years ago
6 0
1). You use the formula A=(pi)r^2
A=(pi)(5)^2
A= 78.5yd
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Oksanka [162]
1.99x+5.5= total cost
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3 years ago
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Solve the following system by any method. –8x – 8y = 0 –8x + 2y = –20
madam [21]
This one is simple since we already have the two x variables.equal. All we have to do is subtract the equations from one another to get the answer.
So i will subtract the left side by the other left side and the right side by the other right side

-8x - 8y -(-8x + 2y) = 0 -(-20)

distribute negative sign

-8x - 8y + 8x - 2y = 0 + 20

do the math
- 10y = 20
Y = -2

plug t into an equation
-8x -8 (-2) = 0

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8 0
3 years ago
Need help with homework
motikmotik

We have two points describing the diameter of a circumference, these are:

\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}

Recall that the equation for the standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})

Now, we replace and solve:

\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}

The center of the circle is (-8,-7), so:

\begin{gathered} h=-8 \\ k=-7 \end{gathered}

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

r^2=\Delta x^2+\Delta y^2

In this case, we will solve the delta with the center coordinate and the B coordinate.

\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}

Therefore, the equation for the standard form of a circle is:

\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}

In conclusion, the equation is the following:

(x+8)^2+(y+7)^2=25

4 0
1 year ago
The 2s in 202 how many times greater
Vlad1618 [11]

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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