Using the Empirical Rule and the Central Limit Theorem, we have that:
- About 68% of the sample mean fall with in the intervals $1.64 and $1.82.
- About 99.7% of the sample mean fall with in the intervals $1.46 and $2.
<h3>What does the Empirical Rule state?</h3>
It states that, for a normally distributed random variable:
- Approximately 68% of the measures are within 1 standard deviation of the mean.
- Approximately 95% of the measures are within 2 standard deviations of the mean.
- Approximately 99.7% of the measures are within 3 standard deviations of the mean.
<h3>What does the Central Limit Theorem state?</h3>
By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation 
.
In this problem, the standard deviation of the distribution of sample means is:
68% of the means are within 1 standard deviation of the mean, hence the bounds are:
99.7% of the means are within 3 standard deviations of the mean, hence the bounds are:
More can be learned about the Empirical Rule at brainly.com/question/24537145
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M<J = m<N ( alternate angles)
m<K = m<M ( alternate angles)
so the third angles must also be equal ( total 180 degrees in each triangle)
Therefor the triangles are similar
3/8 + 1/16= 7/16
so it's c. 7/16
This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
Answer:
(x-1)²+ (y-0.5)²=6.25
Step-by-step explanation:
<u>The standard form of equation of a circle is;</u>
(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius
<u>Finding the mid-point of the given points</u>
(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)
midpoint= {1/2(-1+3), 1/2(2+-1)}
midpoint=(1,0.5)
<u>Finding the radius r; the distance from the center to either of the given two points</u>
Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²
Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then
d=√ (-1-1)² +(2-0.5)²
d= √ (-2)²+(1.5)²
d=√4+2.25⇒√6.25⇒2.5
r=2.5
<u>Equation of the circle</u>
(x-1)² + (y-0.5)²=2.5²
(x-1)²+ (y-0.5)²=6.25
