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2 years ago

500 divided by 18.75

Mathematics

2 answers:

Ivahew [28]2 years ago

8 0

Answer:

26.6

Step-by-step explanation:

im not sure if this is the right answer, but I did my best

GarryVolchara [31]2 years ago

6 0

Answer:

26 $\frac{2}{3}$

Step-by-step explanation:

I'm assuming you want this done without a calculator?

$\frac{500}{18\frac{3}{4}}$ = ?

$\frac{500}{1}$ × $\frac{4}{75}$ = ?

$\frac{2000}{75}$ = ?

$\frac{80}{3}$ = 26 $\frac{2}{3}$

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X=-6+y.x-3y=28. Iii fcugyvycuc

Leto [7]

Answer:

(-6+y)-3y=28

-2y-6=28

-2y=34

y=-17

Then,

x=-6-17

x=-23

Step-by-step explanation:

8 0

2 years ago

Coco's garden has 888 tomato plants, 444 pepper plants, 333 squash plants, and 666 pumpkin plants.

AveGali [126]

888 + 444 + 333 + 666 = 2331 / 7 = 3

3 * 222 = 666

There are 666 of the plants

I hope this helps :)

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2 years ago

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Is this correct plz help me

Lina20 [59]

Answer: Yes!

Step-by-step explanation:

You correctly answered!

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2 years ago

X= degrees 32° x x

Alla [95]

Answer:

32 +x+x=180(Sum of angles of a triangle)

32+2x=180

2x=180-32

2x=148

x=148/2

Therefore,X=74

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1 year ago

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Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

2 years ago