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Tom [10]
3 years ago
15

3x+2y+4+9y= Plz answer

Mathematics
1 answer:
fomenos3 years ago
5 0
<span>3x+2y+4+9y=


Combine like terms:
2y+9y=11y


I believe the answer is 3x+11y+4

(That is unless you know the numbers that y & x equals)</span>
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Free piont (so this will not get delete) 7x8x3=
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Answer:

168

Step-by-step explanation:

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The sum of three numbers is 72. One number is two times 10 and another number is three times 10. What is the third number?
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The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

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Z = 0.8 has a pvalue of 0.7881.

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So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
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vampirchik [111]
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c ≈ 0.0678733 
Hope this helps!
5 0
3 years ago
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