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fgiga [73]
3 years ago
8

Frenchie’s Tool rental charges customers $16 per hour to rent a riding lawnmower. Make a table of ordered pairs in which the x-c

oordinate (domain) represents the number of hours and the y-coordinate (range) represents the total cost of renting the lawnmower for 3, 7, 8, and 12 hours.
Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

\begin{array}{cc}x&y\\ \\3&48\\7&112\\8&128\\12&192\end{array}

Step-by-step explanation:

Let x represents the number of hours and y represents the total cost of renting the lawnmower.

Frenchie’s Tool rental charges customers $16 per hour to rent a riding lawnmower, then renting for x hours costs $16x, thus,

y=16x.

When x = 3, then y=16\cdot 3=48

When x = 7, then y=16\cdot 7=112

When x = 8, then y=16\cdot 8=128

When x = 12, then y=16\cdot 12=192

Therefore, the table is

\begin{array}{cc}x&y\\ \\3&48\\7&112\\8&128\\12&192\end{array}

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The figure shows a vertical section through the
just olya [345]

Answer:

i. 33.51 cm³

ii. 14.14 cm³

iii. 231.61 g

Step-by-step explanation:

(i) the total volume of the paper weight,

Since the paper weight is in the form of a cone, its volume is the volume of a cone V = πD²h/12 where D = diameter of cone = 4 cm and h = height of cone = 8 cm

So, V = πD²h/12

V = π(4 cm)² × 8 cm/12

V = 16π cm² × 8 cm/12

V = 128π cm³/12

V = 402.124 cm³/12

V = 33.51 cm³

(ii) the volume of the wooden portion,

The volume of the wooden portion, V' = πr'²h'/3 where r' = radius of wooden portion and h' = height of wooden portion

From similar triangles in the figure, we have

height of wooden portion, h'/radius of wooden portion, r' = height of paper weight, h/radius of paper weight, r

h'/r' = h/r where r = D/2 where D =diameter of paper weight = 4 cm. So, r = 4 cm/2 = 2 cm

and h' = height of paper weight - height of lead portion = 8 cm - 2 cm = 6 cm

So,

r' = rh'/h = 2 cm × 6 cm/8 cm = 12 cm²/8 cm = 1.5 cm

So, V' = πr'²h'/3

V' = π(1.5 cm)² × 6 cm/3

V' = π2.25 cm² × 2 cm

V' = 4.5π cm³

V' = 14.14 cm³

(iii) the total mass of the paper weight.

The total mass of paper weight, m = mass of wooden portion + mass of lead portion = ρ'V' + ρ"V" where ρ' = density of wood = 0.9 g/cm³, V' = volume of wooden portion = , ρ" = density of lead = 11.3 g/cm³ and V" = volume of lead portion = V - V' = 33.51 cm³ - 14.14 cm³ = 19.37 cm³

So, m = 0.9 g/cm³ × 14.14 cm³ + 11.3 g/cm³ × 19.37 cm³

m = 12.726 g + 218.881 g

m = 231.607

m ≅ 231.61 g

8 0
3 years ago
What is the answer to 64+(-15)+(-5)
MissTica

Answer:

44

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
I REALLY NEED HELP LIKE ASAP
Akimi4 [234]

1. The square on the inside is 8 x 8 = 64

2. The triangle's area is 8x9x1/2= 72 x 1/2 = 36

3. there are 4 triangles so 36 x 4 = (or 72 x 2 ) = 144 :)

7 0
3 years ago
Read 2 more answers
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

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3 years ago
Which of the following questions describes the equation = a/4 -20?
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1) Negative five -5 x 4 = -20 2) Negative eighty -80 / -4 = 20 3) Negative 1/5 (-1/5) x (-20) = 4 4) Negative eighty (-80) / 4 = -20
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