1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AfilCa [17]
3 years ago
15

Line CD passes through points C (1,3) and D (4,-3). If the equation of the line is written in slope intercept form, y=my+b, what

is the value of b?
Mathematics
2 answers:
Lina20 [59]3 years ago
3 0

Answer:

b=5

Step-by-step explanation:

C(1,3) and point D(4,-3)

Since we want the equation in slope intercept form we must first calculate the slope (m):

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\\\m=\frac{-3-3}{4-1}\\ \\m=\frac{-6}{3} \\\\m=-2

By point slope formula and using point C (1,3) we have:y-y_{1}=m(x-x_{1})\\\\y=m(x-x_{1})+y_{1}\\\\y=-2(x-1)+3\\\\y=-2x+2+3\\\\y=-2x+5


So the slope is -2 and the y -intercept (b) is 5.

patriot [66]3 years ago
3 0

Answer: B

Step-by-step explanation:

You might be interested in
g A window is being built and the bottom is a rectangle and the top is a semi-circle. If there is 12 meters of framing materials
photoshop1234 [79]

Answer:

Semicircle of radius of 1.6803 meters

Rectangle of dimensions 3.3606m x 1.6803m

Step-by-step explanation:

Let the radius of the semicircle on the top=r  

Let the height of the rectangle =h  

Since the semicircle is on top of the window, the width of the rectangular portion =Diameter of the Semicircle =2r

The Perimeter of the Window

=Length of the three sides on the rectangular portion + circumference of the semicircle

=h+h+2r+\pi r=2h+2r+\pi r=12

The area of the window is what we want to maximize.

Area of the Window=Area of Rectangle+Area of Semicircle

=2hr+\frac{\pi r^2}{2}

We are trying to Maximize A subject to 2h+2r+\pi r=12

2h+2r+\pi r=12\\h=6-r-\frac{\pi r}{2}

The first and second derivatives are,

Area, A(r)=2r(6-r-\frac{\pi r}{2})+\frac{\pi r^2}{2}}=12r-2r^2-\frac{\pi r^2}{2}

Taking the first and second derivatives

A'\left( r \right) = 12 - r\left( {4 + \pi } \right)\\A''\left( r \right) =  - 4 - \pi

From the two derivatives above, we see that the only critical point  of r

A'\left( r \right) = 12 - r\left( {4 + \pi } \right)=0

r = \frac{{12}}{{4 + \pi }} = 1.6803

Since the second derivative is a negative constant, the maximum area must occur at this point.

h=6-1.6803-\frac{\pi X1.6803}{2}=1.6803

So, for the maximum area the semicircle on top must have a radius of 1.6803 meters and the rectangle must have the dimensions 3.3606m x 1.6803m ( Recall, The other dimension of the window = 2r)

5 0
3 years ago
HELP ME ASAP PLSSSSSSSSSSS
adoni [48]

Answers:

  1. Plane EFGH
  2. Angle 2 and angle 3
  3. Alternate exterior angles
  4. See the explanation below

==================================================

Explanation:

Problem 1

The plane ABCD is the floor of the box or room.

The ceiling plane EFGH is parallel to the floor.

Parallel planes never intersect, must like how parallel lines in 2D never intersect. As such, parallel planes are the same distance apart.

In contrast, something like plane ABFE intersects with ABCD along the segment AB. This shows ABFE is not parallel to ABCD.

----------------------

Problem 2

Same side interior angles, aka consecutive interior angles, are inside the parallel (or nearly parallel) lines. One such example is angle 2 and angle 3. The other pair being angle 6 and angle 7. They must be on the same side of the transversal.

In contrast, alternate interior angles would be something like the pair angle 2 and angle 7. The other pair being angle 3 and angle 6. This time the angles are on alternating or opposite sides of the transversal.

----------------------

Problem 3

Angles 1 and 8 are exterior of the parallel (or nearly parallel) lines. They are on alternating sides of the transversal. Therefore, we consider them to be alternate exterior angles.

----------------------

Problem 4

The use of "alternate" refers to the idea the angles are on opposite or alternating sides of the transversal line. The transversal line is the line that crosses the two other lines that are almost parallel.

I like to think of the parallel (or nearly parallel) lines as train tracks. The transversal is the roadway that crosses both train tracks. Then we could have locations 1 and 8 on opposite sides of the roadways to represent the alternate exterior angles.

As you can probably guess or know by now, the "exterior" is from the angles being outside or exterior of the parallel (or nearly parallel) lines.

4 0
2 years ago
What is the vertex for the parabola shown?
Levart [38]

Answer:

I think is (1, 2) opcion B

7 0
3 years ago
An isosceles right triangle is a right triangle with congruent legs. if the length of each leg is represented by x, what algebra
Marina CMI [18]
By the Pythagoras theorem:-

h^2  = x^2 + x^2  
    (where h = hypotenuse)

h^2 = 2x^2

h = sqrt2 x
8 0
3 years ago
CosX sec^2X tanX - cosX tan^3X = sinX
ch4aika [34]
\cos x\sec^2x\tan x-\cos x\tan^3x=\cos x\tan x\left(\sec^2x-\tan^2x\right)=\sin x\left(\sec^2x-(\sec^2x-1)\right)=\sin x
4 0
3 years ago
Other questions:
  • What are the following solutions to 2x^2-8x-90
    6·1 answer
  • Which of the following accurately illustrates the verbal phrase: Negative seventeen is eight less than a number?
    12·1 answer
  • Convert .19 into a fraction
    8·2 answers
  • Find the range of the sample data 0.62, 1.05, 0.58, 1.17, 1.04, 1.37, 1.32, 0.67, 1.25 1.38, 0.86
    7·2 answers
  • Graphs of Polynomial Functions Gizmo
    5·1 answer
  • How many solutions does 4x + 2(x – 3) = 4x + 2x – 11 have?
    9·2 answers
  • A farmer wants to divide his 2700 km2 of land into two separate pastures for his new horses by building a fence that will enclos
    12·2 answers
  • Please help, Ill mark brainiest if it helps.
    15·1 answer
  • What percent of 513 is 248
    13·2 answers
  • The table below shows how the age of a certain tree is related to the diameter
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!