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meriva
3 years ago
13

30 POINTS! Find the area of the shaded regions.

Mathematics
2 answers:
Artist 52 [7]3 years ago
8 0

Answer:

7pi or ≈21.98 cm²

Step-by-step explanation:

The area of the shaded and non shaded in the circle is pir^2 so pi3^2 so 9pi

the area of the 2 smaller circles is pi1^2*2 so 2pi

9pi-2pi=

7pi cm² =

7pi≈21.98 cm² (with pi as 3.14)

Feliz [49]3 years ago
8 0

Step-by-step explanation:

Area of the large circle =πR²

=3.14×(3)²=3.14×9=28.26cm²

Area of one small circle= πr²= 3.14×1= 3.14cm²

Area of two small circles = 2×3.14 cm²= 6.28cm²

Area of the shaded region= (28.26-6.28)cm²

= 21.98 cm²

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Answer:

<h2>$212.8</h2>

Step-by-step explanation:

If the car loses 11.1% per year, we need to calculate how much money is that:

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Now, in order to calculate this loss per month, we divide it by 12:

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7 0
4 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. What is the volume of t
katen-ka-za [31]

Answer/Step-by-step explanation:

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Therefore,

ANSWER: 416

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3 0
3 years ago
Suppose that the waiting time for a license plate renewal at a local office of a state motorvehicle department has been found to
zysi [14]

The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Given mean of 30 minutes and standard deviation of 7.5 minutes.

In a set with mean d and standard deviation d. , the z score is given as:

Z=(X-d)/s.

where d is sample mean and s is standard deviation.

We have to calculate z score and then p value from normal distribution table.

We have been given d=30, s=7.5

p value of Z when X=44 subtracted by the p value of Z when X=16.

When X=44,

Z=(44-30)/7.5

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P value=0.9686

When X=16

Z=(16-30)/7.5

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Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.

Learn more about z test at brainly.com/question/14453510

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