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3 years ago

What is |-8| –16 –8 8 16

2 answers:

8 0

The answer is 8...when you see those two lines (absolute value lines) it means the same number but as a positive. For example |-12| would just be 12

fomenos3 years ago

3 0

The answer is 8. Those lines are called absolute value. It makes a number positive always.

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What do you call when a relation with each x value has one y value

Nitella [24]

When each x value has only one y value, the relation is a function

5 0

3 years ago

The square of a number is 12 less than 7 times the number. What is the number?

hjlf

Answer:

The number is either 3 or 4

Explanation:

Assume that the number we are looking for is x

The square of the number would be x²

7 times the number would be 7x

We are given that:

square of the number (x²) is 12 less than 7 times the number (7x)

Translating this into an equation, we would have:

x² = 7x - 12

Rearranging the quadratic equation:

x² - 7x + 12 = 0

Now, we factor the equation:

(x-4)(x-3) = 0

This means that:

either x-4 = 0 ..................> x = 4

or x-3 = 0 ........................> x = 3

Let's check if any of the solutions is an extrovert:

For x = 3 .............> (3)² = 7(3) - 12 .........> 9 = 21 - 12 .......> 9 = 9 .......> not extrovert

For x = 4 .............> (4)² = 7(4) - 12 .........> 16 = 28 - 12 .....> 16 = 16 ....> not extrovert

Since we have no restrictions on the number, therefore, both solutions would be accepted

Hope this helps :)

7 0

3 years ago

What the fraction of 0.13

elixir [45]

Answer:

13/100

Step-by-step explanation:

3 0

2 years ago

2.67 +4.56 hjkfghjfvgbn

vfiekz [6]

Answer:

7.23

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Let f(x)= 5/x and g(x)=2x^2+5x What two numbers are not in the domain of f o g?

Igoryamba

Answer:

two number not included in domain are x=0 and x=-5/2

Step-by-step explanation:

Let f(x)= 5/x and g(x)=2x^2+5x

WE need to find out the excluded value in the domain of f o g

f o g is the composition of functions

f o g= f(g(x))

lets plug in g(x) in f(x)

$f(g(x))= f( 2x^2+5x)$

replace 2x^2+5x in f(x)

$f(g(x))= f(2x^2+5x)=\frac{5}{2x^2+5x}$

here we have 2x^2+5x in the denominator

to find the numbers that are in domain we set the denominator =0 and solve for x

Because when denominator becomes 0 the function is undefined

$2x^2+5x=0$

$x(2x+5)=0$

x=0 and 2x+5=0 (subtract 5 on both sides)

2x= -5 (divide by 2 on both sides)

x=-5/2

5 0

3 years ago

Read 2 more answers