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3 years ago

11. GARDEN Emily calculates that the area of a flower garden is 28.125. She measured

Mathematics

1 answer:

Svetlanka [38]3 years ago

7 0

Answer:

A=28.13 Sq Ft

Step-by-step explanation:

Given that the length of the garden = 4.5 ft

Breadth of the garden = 6.25 ft

Area is given by the formula

A=length x breadth

A=4.5 x 6.25 sq ft

A= 28.125 sq ft

Here if we round the area to the nearest hundredth, the area will be

A=28.13 Sq Ft

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Alvin is planning to be out of town for the day, so he asks a friend to dog-sit his 3 dogs. Each dog eats 0.5 pounds of food eve

german

Answer:

2 cans

Step-by-step explanation:

Calculate how many pounds he needs for one day:

3(0.5)=1.5 pounds for each day Alvin is gone ( 3 represents his dogs, .5 is each dog's food)

Convert into ounces:

1.5*16=24 ounces for one day

Question: If dog food is sold in 12 oz cans, how many will he need?

24/12=2 cans

Thus, he will need 2 cans

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3 years ago

It is a linear equation but i don't know how to set the equation up , need help

ryzh [129]

Step-by-step explanation:

x = number of novels

y = number of dictionaries

x = 8y

88x + 208y = 13680

now, using the identity of the first equation in the second equation gives us

88(8y) + 208y = 13680

704y + 208y = 13680

912y = 13680

y = 13680/912 = 15

x = 8y = 8×15 = 120

so, there were 120 novels and 15 dictionaries sold.

7 0

2 years ago

alina1380 [7]

Answer:

the coordinates of the point of x and y is -1÷ 2 and -√3÷ 2

Step-by-step explanation:

The computation of the coordinates of the point is shown below:

The angle is

= 4π ÷ 3

The radius is 1 unit

Now

x = rcos $\theta$ , and y = rsin $\theta$

Now

x = 1cos(4π ÷ 3) = -1÷ 2

y = 1sin(4π ÷ 3) = -√3÷ 2

hence, the corordinates of the point of x and y is -1÷ 2 and -√3÷ 2

8 0

3 years ago

Read 2 more answers

Find the area of a triangle when A = 78°, b = 14 and c = 12.

Cloud [144]

The answer is ...................... c

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3 years ago

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago