Answer: The equation is y = -6*x
Step-by-step explanation:
I suppose that we want to find the equation for a line that passes through the point (-1, 6) and the origin (remember that the origin is the point (0,0))
A general linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If this line passes through the points (x₁, y₁) and (x₂, y₂), then the slope of the line is equal to:
a = (y₂ - y₁)/(x₂ - x₁)
Now we know that our line passes through the points (0, 0) and (-1, 6), then the slope is:
a = (6 - 0)/(-1 - 0) = 6/-1 = -6
Then our equation is something like:
y = -6*x + b
To find the value of b we can use the fact that this line passes through the point (0, 0).
This means that when x = 0, y is also equal to zero.
If we replace these values in the equation we get:
0 = -6*0 + b
0 = b
Then our equation is:
y = -6*x
Answer:
The roots of the polynomial equation in this case would be the intersection of the 2 polynomial functions. which are at x = 4 and x = -3
Step-by-step explanation:
The roots are found by finding the x-values of the intersections of these two cubic polynomial functions.
We could try solving algebraically, but you have the graph.
Answer:
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Step-by-step explanation:
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Answer:
y = [4(x-3)]/3
Step-by-step explanation:
4x = 12+3y
3y = 4x-12
y = [4(x-3)]/3
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