Answer:
a=25
b=7
Step-by-step explanation:
The answer is b because it has the 3 with 6 corresponding.<span />
<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
The answer is no i do not agree
Answer:
8.2 units
Step-by-step explanation:
Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC
<u />
<u>Recall the Law of Cosines</u>
<u />
<u>Identify angles and sides</u>
<u />
<u>Solve for side "a"</u>
<u />
Therefore, the length of line segment BC is about 8.2 units