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alexandr402 [8]

4 years ago

14

How are adding and subtracting rational expressions different from multiplying

1 answer:

Strike441 [17]4 years ago

3 0

Answer:

If the two rational expressions that you want to add or subtract have the same denominator you just add/subtract the numerators which each other. When the denominators are not the same in all expressions that you want to add or subtract as in the example below you have to find a common denominator.

Step-by-step explanation:

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I will give brainliest<br> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

postnew [5]

Answer:

I've labled all in red, hope this helps.

8 0

2 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago

If a+8 = 12 , then a =ayuda por favor

NARA [144]

Answer:

a = 4

Step-by-step explanation:

a+8 = 12

a= 12-8

a=4

7 0

3 years ago

Read 2 more answers

M_6 is (2x - 5)º and m_8 is (x + 5)º.<br> What is m 3?

oksano4ka [1.4K]

m_3 is (7x-4)°

Step-by-step explanation:

which is that m_3 is(7x -4)°.

3 0

4 years ago

Can someone please answer my last post? (its calculus)

ozzi

Answer:

where is ques

Step-by-step explanation:

6 0

4 years ago