Answer:
g-1(x)=SQRT{(x-4)/2} + 4
Step-by-step explanation:
I assume that the 2 is the exponent so ^ represents exponent
We know your function is g(x)=2(x-3)^2+4
For inverse functions we swap x and y values, note g(x) is like the y value
Isolate for y
y=2(x-3)^2+4
x=2(y-3)^2+4
(x-4)/2 = (y-3)^2
SQRT{(x-4)/2} + 4 = y
Therefore g-1(x)=SQRT{(x-4)/2} + 4
Answer:
x = -2
x = 8
Step-by-step explanation:
Excluded values are the ones which make the denominator zero
3x² + x - 10
3x² + 6x - 5x - 10
3x(x + 2) - 5(x + 2)
(x + 2)(3x - 5)
x² - 6x - 16
x² - 8x + 2x - 16
x(x - 8) + 2(x - 8)
(x - 8)(x + 2)
[(x + 2)(3x - 5)] ÷ [(x - 8)(x + 2)]
(3x - 5)/(x - 8)
So excluded values are 8, -2
She will have negative eight dollars. Thats all I can say
When
the ball is in the ground, its height is basically equal to zero thus making
our equation,
<span> -16t^2 + 272t + 1344 = 0</span>
Simplifying
the equation will give us,
<span> - t^2 + 17t + 84 = 0 or t^2 – 17t – 84 = 0</span>
Factoring
out the equation will give us,
<span> (t – 21)(t + 4) = 0</span>
Thus,
t = 21 or t = -4. -4 is an extraneous root. Thus, the answer is t = 21.
<span>Answer:
21 seconds</span>
20m ^2
Explanation:
The top part be be cut into 2 2•2 triangles. A = 4 for both of them
And the rest is a 4•4 square, so A = 16.
4 + 16 = 20
Hope this helps!
