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xxTIMURxx [149]
3 years ago
14

I need the answer to this plzzzz

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0
Gianna worked for 5 hours
Matthew work for 6 hours
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Y decreased by 9is 8
olga55 [171]

Answer:

It's easy to figure it out. The equation we have is 8 = y - 9. We need to isolate y. Simply add 9 to each side of the equation to get this: 17 = y.

ANSWER: 17 = y

8 0
3 years ago
Simplest form of 3/4+1/12
tekilochka [14]

Answer:

5/6

Step-by-step explanation:

7 0
2 years ago
8. Given that DAB and DCB are right angles and BDC = 55°, what is m CAD?
Artyom0805 [142]

Answer:

d

Step-by-step explanation:

d

5 0
3 years ago
Solve the following system by the substitution method. Check the solution.
harina [27]
\left \{ {{3x + 6y = 4x} \atop {x = 8- 2y}} \right.

\left \{ {{3x- 4x + 6y = 0} \atop {x = 8 - 2y}} \right.

\left \{ {{-x + 6y = 0} \atop {x=8 - 2y}} \right.

\left \{ {{-(8-2y) + 6y} \atop {x=8 - 2y}} \right.

\left \{ {{-8+2y +6y = 0} \atop {x=8 - 2y}} \right.

8y = 8
y = 1

x = 8-2y
x = 8-2*1
x = 8-2
x = 6



<span>A.
The system has a single solution. The solution set is (6, 1)</span>
4 0
3 years ago
The area of cross section of the large piston in a hydraulic machine is 1m² and that of small piston is 0.5m².calculate the forc
Dvinal [7]

Answer:

The force that must be applied on the small piston has a magnitude of 500 newtons.

Step-by-step explanation:

By Pascal's Principle, we know that pressure within any point of a closed hydraulic system is the same. Hence, the hydraulic machine can be described by the following model:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Where:

F_{1}, F_{2} - Forces applied on the small and large pistons, in newtons.

A_{1}, A_{2} - Areas of the small and large pistons, in square meters.

If we know that A_{1} = 0.5\,m^{2}, A_{2} = 1\,m^{2} and F_{2} = 1000\,N, then the force to be applied on the small piston is:

F_{1} = \left(\frac{A_{1}}{A_{2}} \right)\cdot F_{2}

F_{1} = \left(\frac{0.5\,m^{2}}{1\,m^{2}} \right)\cdot (1000\,N)

F_{1} = 500\,N

The force that must be applied on the small piston has a magnitude of 500 newtons.

4 0
3 years ago
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