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3 years ago

Which situation could not represent a proportional relationship

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

1/5 does not equal 3/11

Step-by-step explanation:

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I need help finding the area of this shape can you please help

BabaBlast [244]

Answer: 139.27

Step-by-step explanation:

So let find the area of the black swuare the length is 10 and the widith is 10, using bxh the area is 100. Now let find the aea of the semi-circle. The area of a fill circle is pi radius squared so a semi circle area will be 1/2( pi radius squared). The radius is 5 so we can calculate 1/2 of 25 pi equal = 39.27. Now let add the areas: 100+39.27=139.27.

8 0

3 years ago

Can someone help me with answer C? its the last one i need

Dmitry [639]

Using the monthly payment formula, it is found that her down payment should be of $1,419.

<h3>What is the monthly payment formula?</h3>

It is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

In which:

P is the initial amount.

r is the interest rate.

n is the number of payments.

For this problem, the parameters are:

A = 250, r = 0.072, n = 72.

Hence:

r/12 = 0.072/12 = 0.006.

We solve for P to find the total amount of the monthly payments, hence:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

$P\frac{0.006(1.006)^{72}}{(1.006)^{72}-1} = 250$

0.0171452057P = 250

P = 250/0.0171452057

P = $14,581.

The total payment is of $16,000, hence her down payment should be of:

16000 - 14581 = $1,419.

More can be learned about the monthly payment formula at brainly.com/question/26476748

#SPJ1

4 0

2 years ago

The perimeter of a triangle is 28 ft. The medium side is 4 ft longer than the shortest side,while the longest side is twice as l

Aliun [14]

Hope this helps you!

6 0

3 years ago

Select the correct volume.

Bond [772]

Answer:

i think it is 8/125

Step-by-step explanation:

slect B

6 0

3 years ago

Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39

m_a_m_a [10]

$15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479$

4 0

2 years ago