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Ludmilka [50]
4 years ago
11

Write the equation of a line, in SLOPE INTERCEPT FORM, that is perpendicular to the given equation and passes through the given

point.
Starting equation- y = 1/3 + 4

Given Point- (-5, 2)


Any help with this would be great :)
Mathematics
1 answer:
adoni [48]4 years ago
4 0

Step-by-step explanation:

slope interception formula is

y-y1=m(x-x1)

where m is m=y-y1/x-x1 in this case m=-2 because the line we are trying to find is parallel to the given one y=-2x-6 where slope k=-2

so the final equation would be

y-1=-2(x-(-4))

y-1=-2x-2*4

y=-2x-8+1=-2x-7

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Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
Mariana [72]

Answer:

n_1=2.72\\n_2=0.61


Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

a=3\\b=-10\\c=5

Then you have:

 x=\frac{-(-10)+/-\sqrt{(-10)^{2}-4(3)(5)}}{2(3)}

3. Therefore, you obtain the following result:

x_1=2.72\\x_2=0.61



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