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Gnoma [55]
3 years ago
14

Evaluate the function rule for the given value. y=15*3^x for x = -3

Mathematics
1 answer:
DENIUS [597]3 years ago
5 0

Answer: y=\frac{5}{9}

Step-by-step explanation:

It is important to remember that an Exponential function has the following form:

f(x) =a* b^x

Where  “b”  is b > 0 and b \neq 1 , "a" is a coefficient, "x" is the Independent variable and f(x) is the Dependent variable.

In this case, you have the following Exponential Function given in the exercise:

y=15*3^x

If the value of Dependent variable is -3, then:

x=-3

So, you must substitute that value of "x" into the function:

y=15*3^{(-3)}

And now you must evaluate:

1. According the Negative exponent rule:

a^{-n}=\frac{1}{a^n}

Then:

y=\frac{15}{3^{3}}

2. Simplifying, you get:

y=\frac{15}{27}\\\\y=\frac{5}{9}

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Jeff typed a 5-page term paper with 600 words per page. He typed an average of 40 words per minute. If he started typing at 8:15
Leno4ka [110]

Answer:

If Jeff is types 5 pages at 600 words per page, then he types 3,000 words (5 x 600).

So, if Jeff started typing at 8:15 am, he'd finish at 9:30 am.

Step-by-step explanation:

3 0
3 years ago
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In a random sample, 10 students were asked to compute the distance they travel one way to school to the nearest tenth of a mile.
elixir [45]

Answer:

Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232

Step-by-step explanation:

Total number of students = 10 students.

Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8

To find the mean, at first we have to take the sum of all given data and then divide with the number of students.

Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2

Mean = 31.2 / 10 = 3.12

\text{Standard deviation, S} = \sqrt{\frac{\sum x^{2} - \left [ (\sum x)^{2}/n \right ]}{n-1}} \\S = 1.8232 \\\rm The \ Variance = S^{2} = 3.324

5 0
3 years ago
A small box of cereal weighs k grams. A jumbo box of cereal weighs 5 times as much.
mariarad [96]

Answer:

k=m/5

Step-by-step explanation:

explained in the attached pi

3 0
3 years ago
A random sample of 850 births included 434 boys. Use a 0.10 significance level to test the claim that 51.5​% of newborn babies a
Molodets [167]

Answer:

A

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

z = -0.257

P value = P(Z<-0.257) = 0.797

Decision; we fail to reject the null hypothesis. That is, the results support the belief that 51.5​% of newborn babies are​ boys

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Null hypothesis: H0: p = 0.515

Alternative hypothesis: Ha ≠ 0.515

Given;

n=850 represent the random sample taken

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 850

po = Null hypothesized value = 0.515

p^ = Observed proportion = 434/850 = 0.5106

Substituting the values we have

z = (0.5106-0.515)/√(0.515(1-0.515)/850)

z = −0.256677

z = −0.257

To determine the p value (test statistic) at 0.10 significance level, using a two tailed hypothesis.

P value = P(Z<-0.257) = 0.797

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = -0.257) which falls with the region bounded by Z at 0.10 significance level. And also the one-tailed hypothesis P-value is 0.797 which is greater than 0.10. Then we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that at 10% significance level the null hypothesis is valid.

5 0
3 years ago
A number is chosen at random from 1 to 15. Find the probability of
Brut [27]

Answer:

Correct option is

C

5/2

Total no. of numbers=15

No. of prime numbers between 1 to 15=6(2,3,5,7,11,13)

Probability = 15

6 = 52

5 0
3 years ago
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