Point A is located in which quadrant? On a coordinate plane, point A is at (negative 3, 5).
1 answer:
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Answer:
(0, 3 ), (5, 0), (10, -3), (15, -6)
Step-by-step explanation:
3x − 5y = 15
-5y = 3x + 15
y =
Point 1: (0, 3 )
y = -3/5(0) + 3
y = 0 + 3
y = 3
Validate:
3 = -3/5(0) + 3
3 = 3
Point 2: (5, 0)
y = -3/5(5) + 3
y = -3 + 3
y = 0
Validate:
0 = -3/5(5) + 3
0 = 0
Point 3: (10, -3)
y = -3/5(10) + 3
y = -6 + 3
y = -3
Validate:
-3 = -3/5(10) + 3
-3 = -3
Point 4: (15, -6)
y = -3/5(15) + 3
y = -9 + 3
y = -6
Validate:
-6 = -3/5(15) + 3
-6 = -6
Answer:
The answer is
Step-by-step explanation:
we know that
In this problem we have
so
The angle belong to the third or fourth quadrant
The value of is negative
Step 1
Find the value of
Remember
we have
substitute
------> remember that the value is negative
Step 2
Find the value of
we have
substitute