(5x-3)/4 = x/3 +1
5x-3 = 4x/3 +4
5x - 4x/3 = 7
(11/3)x = 7
x = 7/(11/3) = 21/11
Step-by-step explanation:
<u>1</u><u> </u>*9^2 + 4
3
<u>1</u><u> </u>* 81 + 4
3
<u>1</u><u> </u>* 85
3
<u>85</u>
3
=28
Answer:
step by step and the dog got 10 fire wood
The answer is actually choice A
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If we add up the equations straight down we will have 0a+2b = 6
Note how adding the 'a' terms gives us 3a + (-3a) = 3a-3a = 0a. The 0a term is really 0 since 0 times anything is 0. So the 'a' terms will go away
The equation 0a+2b = 6 turns into 0+2b = 6 and that simplifies to 2b = 6
To isolate b, we divide both sides by 2
2b = 6
2b/2 = 6/2
b = 3
We can stop here since only one answer choice has b = 3, which is choice A. However, let's keep going to find the value of 'a'
Plug b = 3 into any equation with 'a' and 'b', then solve for 'a'
3a+4b = 9
3a+4*3 = 9
3a+12 = 9
3a+12-12 = 9-12
3a = -3
3a/3 = -3/3
a = -1
So a = -1 and b = 3 pair up to form (a,b) = (-1,3)
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To check, plug this ordered pair back into both equations
Equation 1:
3a+4b = 9
3*(-1)+4*3 = 9
-3+12 = 9
9 = 9
Equation 1 has been checked out
Equation 2:
-3a-2b = -3
-3(-1)-2(3) = -3
3 - 6 = -3
-3 = -3
this is true as well
So this confirms that the final answer is choice A
to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.
so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?
y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)
hmmm x = 2, what is "y"?
y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).
then just plot those, and run a line through them.
