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Virty [35]
2 years ago
15

In 2009, a town's population was about 9,000 residents. In 2014, the population was about 12,500 residents. Which linear model r

epresents the town's population, p, as a function of t, the time in years after 2007
Mathematics
2 answers:
NeX [460]2 years ago
6 0

Answer:

Population function (Based on 2007) =  7,600 + 700n

Step-by-step explanation:

Given:

Population in 2009 = 9,000

Population in 2014 = 12,500

Computation:

Increase in population per year = [12,500 - 9,000] / 5

Increase in population per year = 700

Population in 2007 = 9,000 - [2 x 700]

Population in 2007 = 7,600

Population function (Based on 2007) =  7,600 + 700n

n = number of year

trapecia [35]2 years ago
5 0

Answer:

p(t)=700t+7600

Step-by-step explanation:

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Answer:7x-29

Step-by-step explanation: simplify and open the brackets.remember that a letter and a number cannot be sumed up but can my multipled together

5 0
2 years ago
Help plz idk okhehehehehe​
TiliK225 [7]
That is the answer for the first one

6 0
2 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
2 years ago
What is the missing reason in step 5?
DENIUS [597]

Answer:

The Correct Answer On Edgen2020 Is

A) Linear pair postulate.

Good Luck!! :))

7 0
2 years ago
Read 2 more answers
Need help with this problem for my cousin
yKpoI14uk [10]
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).

There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)

Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).

95 ft. squared is the area of the entire figure. Hope this helped you.
3 0
3 years ago
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