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3 years ago

Emma ran 4 1/2 miles. For 3/4 of her run,she ran uphill. How many miles did she run uphill?

Mathematics

2 answers:

Gemiola [76]3 years ago

6 0

Answer:

its c hope it helps not totally sure but yeah

Step-by-step explanation:

emmainna [20.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

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For the following right triangle, find the side length. Round your answer to the nearest hundredth

IRINA_888 [86]

Answer:9.75

Step-by-step explanation:12x12 =144 and 7x7= 49 subtract 144-49 and get 95 the square root of 95 is approximately 9.747 rounded to the nearest hundredths place is 9.75

4 0

3 years ago

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in the balcony of a theatre there are 420 seats. the number of seats in each row is 14 more than the number of rows. find the nu

ki77a [65]

420 divided by 14 = 30

There are 30 rows

7 0

3 years ago

7400 dollars is placed in an account with an annual interest

Anastasy [175]

Answer:

Step-by-step explanation:

We have the following equation for compounding annual interest

AV=PV(1+i)ⁿ

We have

19200=7400(1+.06)ⁿ

Solve for n

divide both sides by 7400

2.594=(1.06)ⁿ

then use the following rule for exponents

$x^y=z\\log_xz=y$

which means that

$log_{1.06}2.594=n$

Solve and get

16.362

which rounds to 17

6 0

3 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

5 0

3 years ago

What, is commercial Mathematics...

Delvig [45]

Answer:

I believe Commercial Mathematics is the kind of mathematics for the bussiness world. Where you calculate: There are 12 productions and three companies. Two companies already took 8 productions. How many productions will the last company take? Stuff like that.

6 0

3 years ago

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