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pickupchik [31]
4 years ago
11

Find the limit, if it exists. (If an answer does not exist, enter DNE.)

Mathematics
1 answer:
Charra [1.4K]4 years ago
6 0

Note that your function can be written as

\begin{cases}\frac{2-(-x)}{2+x}&\text{if } x0\end{cases} = \begin{cases}\frac{2+x}{2+x}&\text{if } x0\end{cases} = \begin{cases}1&\text{if } x0\end{cases}

So, if x is negative, your function is identically equal to 1. In particular, the limit as x approaches -2 will be 1 as well.

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