201 minutes because 6 multiplied by 33.5 = 201 minutes
Answer:
Step-by-step explanation:
![A=\pi r^2\\ \\ A=\pi(2.75ft(yd/3ft))^2\\ \\ A\approx 2.64 yd^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%5C%5C%20%5C%5C%20A%3D%5Cpi%282.75ft%28yd%2F3ft%29%29%5E2%5C%5C%20%5C%5C%20A%5Capprox%202.64%20yd%5E2)
Answer:
![\sigma = 0.07770](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.07770)
Step-by-step explanation:
Given
The above table
Required
The standard deviation
First, calculate the class mid-point. This is the average of the class interval.
The mid-point x is:
![x_1 = \frac{1}{2}(15.3 + 15.6) =\frac{1}{2} * 30.9 = 15.45](https://tex.z-dn.net/?f=x_1%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2815.3%20%2B%2015.6%29%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%2030.9%20%3D%2015.45)
![x_2 = \frac{1}{2}(15.6 + 15.9) =\frac{1}{2} * 31.5 = 15.75](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2815.6%20%2B%2015.9%29%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%2031.5%20%3D%2015.75)
![x_3 = \frac{1}{2}(15.9 + 16.2) =\frac{1}{2} * 32.1 = 16.05](https://tex.z-dn.net/?f=x_3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2815.9%20%2B%2016.2%29%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%2032.1%20%3D%2016.05)
![x_4 = \frac{1}{2}(16.2 + 16.5) =\frac{1}{2} * 32.7 = 16.35](https://tex.z-dn.net/?f=x_4%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2816.2%20%2B%2016.5%29%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%2032.7%20%3D%2016.35)
![x_5 = \frac{1}{2}(16.5 + 16.8) =\frac{1}{2} * 33.3 = 16.65](https://tex.z-dn.net/?f=x_5%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2816.5%20%2B%2016.8%29%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%2033.3%20%3D%2016.65)
So, we have:
![\begin{array}{cccccc}x & {15.45} & {15.75} & {16.05} & {16.35} & {16.65} \ \\ f & {14} & {25} & {84} & {18} & {9} \ \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcccccc%7Dx%20%26%20%7B15.45%7D%20%26%20%7B15.75%7D%20%26%20%7B16.05%7D%20%26%20%7B16.35%7D%20%26%20%7B16.65%7D%20%5C%20%5C%5C%20f%20%26%20%7B14%7D%20%26%20%7B25%7D%20%26%20%7B84%7D%20%26%20%7B18%7D%20%26%20%7B9%7D%20%5C%20%5Cend%7Barray%7D)
Calculate mean
![\bar x = \frac{\sum fx}{\sum f}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B%5Csum%20fx%7D%7B%5Csum%20f%7D)
![\bar x = \frac{15.45 * 14 + 15.75 * 25 + 16.05 * 84 + 16.35 * 18 + 16.65 * 9}{14 + 25 + 84 + 18 + 9}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B15.45%20%2A%2014%20%2B%2015.75%20%2A%2025%20%2B%2016.05%20%2A%2084%20%2B%2016.35%20%2A%2018%20%2B%2016.65%20%2A%209%7D%7B14%20%2B%2025%20%2B%2084%20%2B%2018%20%2B%209%7D)
![\bar x = \frac{2402.4}{150}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B2402.4%7D%7B150%7D)
![\bar x = 16.016](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2016.016)
The standard deviation is:
![\sigma = \sqrt{\frac{\sum(x_i - \bar x)^2}{\sum f}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B%5Csum%28x_i%20-%20%5Cbar%20x%29%5E2%7D%7B%5Csum%20f%7D%7D)
![\sigma = \sqrt{\frac{(15.45 - 16.016)^2+ (15.75 - 16.016)^2+ (16.05 - 16.016)^2+ (16.35 - 16.016)^2+ (16.65 - 16.016)^2}{14 + 25 + 84 + 18 + 9}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B%2815.45%20-%2016.016%29%5E2%2B%20%2815.75%20%20-%2016.016%29%5E2%2B%20%2816.05%20%20-%2016.016%29%5E2%2B%20%2816.35%20%20%20-%2016.016%29%5E2%2B%20%2816.65%20%20-%2016.016%29%5E2%7D%7B14%20%2B%2025%20%2B%2084%20%2B%2018%20%2B%209%7D%7D)
![\sigma = \sqrt{\frac{0.90578}{150}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B%5Cfrac%7B0.90578%7D%7B150%7D%7D)
![\sigma = \sqrt{0.00603853333}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Csqrt%7B0.00603853333%7D)
Answer:
-1
Step-by-step explanation:
We can plug in -3 for x and solve:
f(-3) = -3 + 2
= -1
Answer:
Step-by-step explanation:
Let y = -A cos B(t -c) + D
A, amplitude = 20ft
Period = 2π / B ( B = π / 15)
= 30
c = 0
Vertical shift D = 21.5 ft
Equation becomes
![y= -20 \cos \frac{\pi}{15}( t-0)+21.5](https://tex.z-dn.net/?f=y%3D%20-20%20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B15%7D%28%20t-0%29%2B21.5)
![\to y=-20\cos \frac{\pi}{15} t+21.5](https://tex.z-dn.net/?f=%5Cto%20y%3D-20%5Ccos%20%5Cfrac%7B%5Cpi%7D%7B15%7D%20t%2B21.5)
a) Top of the ferris wheel is
t = 15sec, 45sec, height = 41.5ft
b) At the bottom of the ferris wheel
t = 0, 30sec, 60 sec
height = 1.5ft
c) Exact middle of the ferris wheel
t = 15/ 2 = 7.5sec, 22.5sec, 37.5sec, 52.5sec
d) ![f(t) or h = -20 \cos (\frac{\pi}{15} t)+21.5](https://tex.z-dn.net/?f=f%28t%29%20or%20h%20%3D%20-20%20%5Ccos%20%28%5Cfrac%7B%5Cpi%7D%7B15%7D%20t%29%2B21.5)