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3 years ago

Find the area under the standard normal curve between z=0.45 and z=1.13

Mathematics

1 answer:

Law Incorporation [45]3 years ago

8 0

Step-by-step explanation:

the answer is in the above image

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In the diagram below, trapezoid ABCD maps to trapezoid A’B’C’D’

snow_tiger [21]

Answer:

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

$A \to A'$

$B \to B'$

$C \to C'$

$D \to D'$

Hence, C' corresponds to C

6 0

2 years ago

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What is the slip of the line 4x-2y=5

Eddi Din [679]

If you mean slope.. the equation to set up is y=mx+b. Using this, and finding out the answer m=2.

Hope this helped!

4 0

3 years ago

True, false, or open 4y+8=6y+3

Soloha48 [4]

Answer:

its open you never know tho

Step-by-step explanation:

3 0

3 years ago

2. Find the area. The figure is not drawn to scale. 4 cm 17 cm

BabaBlast [244]

area=base x height so i’m thinking it’s 4x17=68

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2 years ago

Plato combining functions mastery test please help

just olya [345]

Answer:

Choice: B.

Step-by-step explanation:

Operations With Functions

Given the functions:

$f(x)=\sqrt[3]{12x+1}+4$

$g(x)=\log(x-3)+6$

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

$(g-f)(x)= g(x) - f(x)$

$(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)$

Operating:

$(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4$

Joining like terms:

$\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}$

Choice: B.

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3 years ago

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