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Cloud [144]
3 years ago
12

Find the area under the standard normal curve between z=0.45 and z=1.13

Mathematics
1 answer:
Law Incorporation [45]3 years ago
8 0

Step-by-step explanation:

the answer is in the above image

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In the diagram below, trapezoid ABCD maps to trapezoid A’B’C’D’
snow_tiger [21]

Answer:

C'

Step-by-step explanation:

Given

ABCD to A'B'C'D'

Required

Corresponding angle of C

ABCD to A'B'C'D' means that the following angles are corresponding

A \to A'

B \to B'

C \to C'

D \to D'

Hence, C' corresponds to C

6 0
2 years ago
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What is the slip of the line 4x-2y=5
Eddi Din [679]

If you mean slope.. the equation to set up is y=mx+b. Using this, and finding out the answer m=2.

Hope this helped!

4 0
3 years ago
True, false, or open 4y+8=6y+3
Soloha48 [4]

Answer:

its open you never know tho

Step-by-step explanation:


3 0
3 years ago
2. Find the area. The figure is not drawn to scale.<br> 4 cm<br> 17 cm
BabaBlast [244]
area=base x height so i’m thinking it’s 4x17=68
7 0
2 years ago
Plato combining functions mastery test please help
just olya [345]

Answer:

<em>Choice: B.</em>

Step-by-step explanation:

<u>Operations With Functions</u>

Given the functions:

f(x)=\sqrt[3]{12x+1}+4

g(x)=\log(x-3)+6

The function (g-f)(x) can be obtained by replacing both functions and subtracting them as follows:

(g-f)(x)= g(x) - f(x)

(g-f)(x)= \log(x-3)+6 - (\sqrt[3]{12x+1}+4)

Operating:

(g-f)(x)= \log(x-3)+6 - \sqrt[3]{12x+1}-4

Joining like terms:

\boxed{(g-f)(x)= \log(x-3) - \sqrt[3]{12x+1}+2}

Choice: B.

7 0
3 years ago
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