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sergeinik [125]
3 years ago
6

Please help A and B plz

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
To solve the given problem you have to use these formula's. 

Perimeter= length² + width² 

Area=length×width
Elden [556K]3 years ago
6 0
Perimeter= length+length+width+width
Area=length×width
And then substitute..
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Hey can somebody help me? I know it seems easy but I forgot the process on how to do this. Thanks in advance!
joja [24]
The answer is 1, because you have got lets say 1 1/2 chocolate (it means one and a half) then if you eat the 1/2 (the half) then you have got 1 chocolate left.
7 0
3 years ago
Solve the equation 5x+3÷4=7. Explain and justify each step in your solution process.
Anettt [7]
5x+3÷4=7
5x+.75=7
-.75 -.75
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divide by 5 on both sides
x= 1.25

please mark brainliest
3 0
3 years ago
Anybody know the answer?
gavmur [86]

Answer:

count the colors

Step-by-step explanation:

count the green, then the red, then the blue

7 0
3 years ago
Help please i wanna get my assignments done by today so anyone willing to help please help
Blizzard [7]

Answer:

A - 4/25

Step-by-step explanation:

out of 50 trials Nadia got oraange 8 times

8 out of 50 = 8/50

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4 0
3 years ago
Read 2 more answers
Write 85% as it's fraction, as simply as possible​
cricket20 [7]

Hey ! there

Answer:

  • Simplest fraction form of 85% is <u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>.</u>

Step-by-step explanation:

Question says that we have to write the <u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>as </u><u>it's </u><u>fraction</u><u> </u><u>.</u>

<u>Solution </u><u>:</u><u> </u><u>-</u>

\quad \longrightarrow  \qquad \:85\%

We know that ,

  • Percent ( % ) = <u>1</u><u>/</u><u>100</u>

So ,

\quad \longrightarrow  \qquad \: 85 \times \dfrac{1}{100} \:

or ,

\quad \longrightarrow  \qquad \: \dfrac{85}{100}

Reducing the fraction by cancelling it by 5 :

\quad \longrightarrow  \qquad \: \dfrac{ \cancel{85}}{ \cancel{100}}

We get :

\quad \longrightarrow  \qquad \:      \pink{\underline{\boxed{\frak{\dfrac{17}{20} }}}} \quad \bigstar

Now , we can't reduce 17/20 .

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>is </u><u>the </u><u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
4 0
2 years ago
Read 2 more answers
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