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sergeinik [125]
3 years ago
6

Please help A and B plz

Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
To solve the given problem you have to use these formula's. 

Perimeter= length² + width² 

Area=length×width
Elden [556K]3 years ago
6 0
Perimeter= length+length+width+width
Area=length×width
And then substitute..
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What is the ratio 1:3 when turned into a fraction?
Anika [276]
If you turn the ratio 1:3 into a fraction it would be 1 over 3 I hope this helps
6 0
3 years ago
5 to the 4 power and 2
stepladder [879]

Answer:

627

Step-by-step explanation:

5 {}^{4}  + 2 = 627

6 0
3 years ago
Which piece of additional information can be used to prove △CEA ~ △CDB?
8_murik_8 [283]
<h3>Answer:</h3>

∠BDC and ∠AED are right angles

<h3>Step-by-step explanation:</h3>

Because ∠C ≅ ∠C, the additional bit of information above can be used to show AA similarity.

____

None of the other offered choices says anything about <em>both</em> triangles. In order to show similarity, you need information about corresponding parts of the <em>two</em> triangles. Information about one triangle alone is not sufficient.

5 0
3 years ago
9. Mr. McDonald has $500.00 to spend at a bicycle store. All prices listed
Nataliya [291]

Answer:

This will explain it

Step-by-step explanation:

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.

Spent so far:

... 273.98 + 3×7.23 +42.36 = 338.03

Remaining available funds:

... 500.00 -338.03 = 161.97

The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.

Mr. Traeger can buy two (2) cycling outfits with the remaining money.

_____

The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.

8 0
3 years ago
Use the rectangle hexagon with side length 10 meters to fill in the missing information
Vlada [557]

Answer:

A_h=150\sqrt{3}\ m^2

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

x=5 m

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

\theta=360/12=30^o

Now we have \theta, the height of the triangle y is easily found by

\displaystyle tan30^o=\frac{x}{y}

Solving for y

\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}

The value of z can be found by using

\displaystyle sin30^o=\frac{x}{z}

\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10

The area of the triangle is

\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}

The area of the hexagon is 12 times the area of the triangle, thus

\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}

\boxed{A_h=150\sqrt{3}\ m^2}

6 0
3 years ago
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