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Akimi4 [234]
3 years ago
13

Fill in the blank questions are considered______ questions a response b matching c best answer d none of these

Mathematics
2 answers:
Natali [406]3 years ago
8 0

Answer:

C. The best Answer

Step-by-step explanation:

choli [55]3 years ago
6 0

Answer:

A: Response

Step-by-step explanation:

A fill in the blank question is considered a response question. A test's directions often clarify any questions a student might have about answering a response question.

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40 - 59 ⇒ 6

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What are the solutions to the quadratic equation 4x2=64?
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X=4 or X=-4 because 4(4)^2 does =64
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(0,5)

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2 years ago
What percent is 608 million of 845 million
wlad13 [49]
Hello,

To find the percentage, simply divide the smaller number to the larger number. In this situation, we divide 608 million by 845 million, which will get you:
0.719526627219. At this point, move the decimal place 2 places to the right to get the percent form of the decimal. Let's also round this decimal up.

After you move the decimal place, it's now 71.9526627219, and if we round it to the nearest 10th, it would be 71.95%.

In conclusion, the percent is 71.95%.

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May
3 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
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