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2 years ago

I need help quick I do K12 and this doesn’t make sense to me AT ALL

Mathematics

2 answers:

AleksandrR [38]2 years ago

3 0

Answer:

Step-by-step explanation:

mean

I think.

Rainbow [258]2 years ago

3 0

The answer is Mode because the graph start showing its actions for example when it starts from zero it rises up to the mode the. Start making its way down

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Divide the rational expressions and express in simplest form. When typing your answer for the numerator and denominator be sure

Veseljchak [2.6K]

Dividing by a fraction is equivalent to multiply by its reciprocal, then:

$\begin{gathered} \frac{3y^2-7y-6}{2y^2-3y-9}\div\frac{y^2+y-2}{2y^2+y-3^{}}= \\ =\frac{3y^2-7y-6}{2y^2-3y-9}\cdot\frac{2y^2+y-3}{y^2+y-2}= \\ =\frac{(3y^2-7y-6)(2y^2+y-3)}{(2y^2-3y-9)(y^2+y-2)} \end{gathered}$

Now, we need to express the quadratic polynomials using their roots, as follows:

$ay^2+by+c=a(y-y_1)(y-y_2)$

where y1 and y2 are the roots.

Applying the quadratic formula to the first polynomial:

$\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{7\pm\sqrt[]{(-7)^2-4\cdot3\cdot(-6)}}{2\cdot3} \\ y_{1,2}=\frac{7\pm\sqrt[]{121}}{6} \\ y_1=\frac{7+11}{6}=3 \\ y_2=\frac{7-11}{6}=-\frac{2}{3} \end{gathered}$

Applying the quadratic formula to the second polynomial:

$\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{-1\pm\sqrt[]{1^2-4\cdot2\cdot(-3)}}{2\cdot2} \\ y_{1,2}=\frac{-1\pm\sqrt[]{25}}{4} \\ y_1=\frac{-1+5}{4}=1 \\ y_2=\frac{-1-5}{4}=-\frac{3}{2} \end{gathered}$

Applying the quadratic formula to the third polynomial:

$\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{3\pm\sqrt[]{(-3)^2-4\cdot2\cdot(-9)}}{2\cdot2} \\ y_{1,2}=\frac{3\pm\sqrt[]{81}}{4} \\ y_1=\frac{3+9}{4}=3 \\ y_2=\frac{3-9}{4}=-\frac{3}{2} \end{gathered}$

Applying the quadratic formula to the fourth polynomial:

$\begin{gathered} y_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ y_{1,2}=\frac{-1\pm\sqrt[]{1^2-4\cdot1\cdot(-2)}}{2\cdot1} \\ y_{1,2}=\frac{-1\pm\sqrt[]{9}}{2} \\ y_1=\frac{-1+3}{2}=1 \\ y_2=\frac{-1-3}{2}=-2 \end{gathered}$

Substituting into the rational expression and simplifying:

$\begin{gathered} \frac{3(y-3)(y+\frac{2}{3})2(y-1)(y+\frac{3}{2})}{2(y-3)(y+\frac{3}{2})(y-1)(y+2)}= \\ =\frac{3(y+\frac{2}{3})}{2(y+2)}= \\ =\frac{3y+2}{2y+4} \end{gathered}$

8 0

1 year ago

Find the 8th term of the geometric sequence whose common ratio is 2/3 and whose first term is 7

motikmotik

Answer:

The 8th term of the sequence is 896/2187.

Step-by-step explanation:

We want to find the 8th term of a geometric sequence whose common ratio is 2/3 and whose first term is 7.

We can write a direct formula. Recall that the direct formula of a geometric sequence is given by:

$\displaystyle x_{n} = a\left(r\right)^{n-1}$

Where a is the initial term and r is the common ratio.

Substitute:

$\displaystyle x_{n} = 7\left(\frac{2}{3}\right)^{n-1}$

To find the 8th term, let n = 8. Substitute and evaluate:

$\displaystyle \begin{aligned} x_{8} &= 7\left(\frac{2}{3}\right)^{(8) - 1} \\ \\ &= 7\left(\frac{2}{3}\right)^{7} \\ \\ &= 7\left(\frac{128}{2187}\right) \\ \\ &= \frac{896}{2187} = 0.4096...\end{aligned}$

In conclusion, the 8th term of the sequence is 896/2187.

8 0

2 years ago

Need help. arrange the polynomial in descending order, x5+x+2x³+6+2x²= ______

kirill [66]

X⁵+ x +2x³ + 6+ 2x² = x⁵ + 2x³ +2x² + x + 6

5 0

3 years ago

Read 2 more answers

The perimeter of a triangle garden is 54 feet. Find the length of the three sides if the middle length side is 4 feet greater th

jeka94

9514 1404 393

Answer:

9 ft, 22 ft, 23 ft

Step-by-step explanation:

Let s represent the length of the shortest side. Then the middle length side is (2s+4) and the longest side is (3s-4). The perimeter is the sum of the side lengths:

54 = s +(2s +4) +(3s -4)

54 = 6s . . . . . . . . . . . . . . collect terms

9 = s . . . . . . . . . . divide by 6

2s+4 = 2·9 +4 = 22

3s -4 = 3·9 -4 = 23

The lengths of the three sides are 9 feet, 22 feet, and 23 feet.

6 0

2 years ago

Which of the following best describes how to use of the addition property of equality to isolate the variable x below?. . 5 = x

sergiy2304 [10]

The best answer is C.add 2 to both sides of the equation.
5=x-2
5+2=x-2+2
7=x-0
x=7

5 0

3 years ago