The town swimming pool is d feet deep. The width of the pool is 10 feet greater than 5 times the depth. The length of the pool i
s 25 feet greater than the width.
a. Write and simplify an expression to represent the volume of the pool.
b. If the pool holds 51,000 ft cubed of water, what are he dimensions of the pool?
a. Write and simplify an expression to represent the volume of the pool.
b. If the pool holds 51,000 ft cubed of water, what are he dimensions of the pool?
1 answer:
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Answer:
Volume of Gold = 0.4 cubic feet.
Step-by-step explanation:
First we have to make sure the units are same as the units the answer is required in.
Answer should be given in cubic feet.
Density is given in pounds per cubic foot. And Mass is given in pounds. So units are in order. Therefore, we can go ahead with the calculation.
The Density of Gold = [Mass of Gold/Volume of Gold]
By substituting values,
ponds per cubic foot = [
pounds / Volume of gold]
Making Volume of God the subject of the equation,
Volume of Gold = [ pounds / tex]1204[/tex] ponds per cubic foot ]
Volume of Gold = 0.4 cubic feet.