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olga55 [171]
3 years ago
7

The town swimming pool is d feet deep. The width of the pool is 10 feet greater than 5 times the depth. The length of the pool i

s 25 feet greater than the width.
a. Write and simplify an expression to represent the volume of the pool.

b. If the pool holds 51,000 ft cubed of water, what are he dimensions of the pool?

Mathematics
1 answer:
Serjik [45]3 years ago
7 0
25×10=250 length then 51,000÷250 I do division different. hope this helps

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Verizon [17]

Answer:

6 is the correct answer

Step-by-step explanation:

4*2=8

3*2=6

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Find the length of the hypotenuse
Darina [25.2K]

Answer:

The Hypotenuse is side just opposite to the right angle.

Step-by-step explanation:

By Pythagoras' theorem,

c^2=a^2+b^2

c^2(hypotenuse to be found)= 30^2+ 16^2

<em>c^2=1156 </em>

<em><u>Therefore, c ( i.e. the hypotenuse) will be the square root of 1156. </u></em>

<em><u>The square root of 1156 is 34. </u></em>

<h2><em><u>Thus, c ( hypotenuse) = 34</u></em></h2>

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What is 6.1 divided by 9<br> (step by step)
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Use division or long division (ignore the decimal point)
Then put the decimal in the same spot as the dividend (the number being divided)
6 0
3 years ago
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What is the answer to this?<br> Thank you
Andre45 [30]
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6 0
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Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

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                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

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