Factor
find wht 2 numbers add to 8 and multiply to 3
none do
use quadratic formula which can be used when
ax^2+bx+c=0
x=
a=1
b=8
c=3
x=
x=
x=
x=
x=
x=
or x=
aprox x=-7.60555 or x=-0.394449
It is true because
when you separate 2y^2 +9y -18, you are supposed to get the factors
(2y-3)(y+6), when you multiply this it gives you the first equation, we know
this because when we multiply the first term it gives us exactly 2y^2 and if we
multiply the last ones it gives you -18, now here is the tricky part, when we
multiply the middle part we get 12y and -3y, when we add these up we get 9y,
now is that the same middle as in the equation? Yes… then our factors are correct
making this true
Hope this helps
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
0 Pretend that is theta XD
cot 0 = 
Find tan 0.
tan 0 = 
tan 0 = 
tan 0 = 
cot 0 =
cot 0 = 
Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)
cot 0 = 
cot 0 = 
Multiply √5 to the numerator and the denominator
cot 0 = 
cot 0 = 
