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3 years ago

what are the solutions of the equations x^2+14x=-130? (1point) a.2,-16 b.10,-13 c.-2,16 d.no solution

1 answer:

5 0

$x^2+14x=-130\\
x^2+14x+49=-81\\
(x+7)^2=-81$

no solutions in $\mathbb{R}$

in $\mathbb{C}$
$x+7=-\sqrt{-81} \vee x+7=\sqrt{-81}\\
x=-7-\sqrt{-81} \vee x=-7+\sqrt{-81}\\
x=-7-9i \vee x=-7+9i\\$

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2 years ago

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Answer:

μ = 1 The firm expects that one oil exploration will be successful.

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2 years ago

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wariber [46]

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Step-by-step explanation:

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3 years ago

Consider the triangle A(4,0), B(-2,4), C(0,6) What will be the equation of the altitude BM?

katovenus [111]

Answer:

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Step-by-step explanation:

AC formula: m = (6-0)/(0-4) = -3/2

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y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54

M (4/13 , 72/13) or (0.31 , 5.54)

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2 years ago

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