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3 years ago

12

Find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using it. lim x → (π/2)+

cos x 1 − sin x

1 answer:

BaLLatris [955]3 years ago

4 0

Looks like the limit is

$\displaystyle\lim_{x\to\pi/2^+}\frac{\cos x}{1-\sin x}$

which yields an indeterminate form $\dfrac00$ . Rewriting as

$\dfrac{\cos x(1+\sinx)}{(1-\sin x)(1+\sin x)}=\dfrac{\cos x(1+\sin x)}{1-\sin^2x}=\dfrac{1+\sin x}{\cos x}$

we see the numerator approaches 1 + 1 = 2, while the denominator approaches 0. Since $\cos x$ for $x$ near $\dfrac\pi2$ with $x>\dfrac\pi2$ , the limit is $-\infty$ .

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Item 6 sq−→sq→ bisects ∠rst∠rst, sp−→sp→ bisects ∠rsq∠rsq, and sv−→sv→ bisects ∠rsp∠rsp. the measure of ∠vsp∠vsp is 17°17°. find

Stolb23 [73]

<span>Angle TSQ measures 68 degrees. When a ray bisects an angle, it divides it into two equal parts. Each part is one-half the measurement of the original angle. Several rays are described as bisecting different angles. I would sketch a diagram to keep track of all the different rays and angles.

A. Since angle RST is bisected by ray SQ, angle RSQ and angle QST are each half the size of angle RST.

B. Since angle RSQ is bisected by ray SP, angle RSP and angle PSQ are each half the size of angle RSQ.

C. Since angle RSP is bisected by ray SV, angle RSV and angle VSP are each half the size of angle RSP. We are given the measurement of angle VSP as 17 degrees. To find the measure of angle RSP, we notice in statement C above that VSP is half the size of angle RSP. If we double angle VSP's measurement (multiply by 2), we get angle RSP measures 34 degrees. Using similar logic and statement B above, we double RSP's measurement of 34 to get angle RSQ's measurement. Double 34 is 68, angle RSQ's measurement in degrees. From statement A above, we notice that RSQ's measurement is equal to that of angle QST's. Therefore, angle QST also measures 68 degrees. However, the question asks us to find the measurement of angle TSQ. However, angle QST and angle TSQ are the same. Either description can be used. Therefore, the measurement of angle TSQ is 68 degrees.</span>

3 0

3 years ago

What is 3/8 equivalent to

grin007 [14]

3/8 is equivalent to 0.375.

7 0

3 years ago

Bonds are a(n) _______________ instrument.

stiks02 [169]

Answer:

indebtedness

Step-by-step explanation:

3 0

3 years ago

The sum of 4 consecutive odd numbers is 1040. Find the numbers.

Gennadij [26K]

Answer:

257+259+261+263 = 1040

Step-by-step explanation:

4 0

3 years ago

What is the equation for the plane illustrated below?

TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

$a\cdot x + b\cdot y + c\cdot z = d$

Where:

$x$ , $y$ , $z$ - Orthogonal inputs.

$a$ , $b$ , $c$ , $d$ - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0), (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

$y = m\cdot x + b$

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - x-Intercept, dimensionless.

If $x_{1} = 2$ , $y_{1} = 0$ , $x_{2} = 0$ and $y_{2} = 2$ , then:

Slope

$m = \frac{2-0}{0-2}$

$m = -1$

x-Intercept

$b = y_{1} - m\cdot x_{1}$

$b = 0 -(-1)\cdot (2)$

$b = 2$

The equation of the line in the xy-plane is $y = -x+2$ or $x + y = 2$ , which is equivalent to $3\cdot x + 3\cdot y = 6$ .

yz-plane (0, 2, 0) and (0, 0, 3)

$z = m\cdot y + b$

$m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}$

Where:

$m$ - Slope, dimensionless.

$y_{1}$ , $y_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - y-Intercept, dimensionless.

If $y_{1} = 2$ , $z_{1} = 0$ , $y_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

y-Intercept

$b = z_{1} - m\cdot y_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the yz-plane is $z = -\frac{3}{2}\cdot y+3$ or $3\cdot y + 2\cdot z = 6$ .

xz-plane (2, 0, 0) and (0, 0, 3)

$z = m\cdot x + b$

$m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}$

Where:

$m$ - Slope, dimensionless.

$x_{1}$ , $x_{2}$ - Initial and final values for the independent variable, dimensionless.

$z_{1}$ , $z_{2}$ - Initial and final values for the dependent variable, dimensionless.

$b$ - z-Intercept, dimensionless.

If $x_{1} = 2$ , $z_{1} = 0$ , $x_{2} = 0$ and $z_{2} = 3$ , then:

Slope

$m = \frac{3-0}{0-2}$

$m = -\frac{3}{2}$

x-Intercept

$b = z_{1} - m\cdot x_{1}$

$b = 0 -\left(-\frac{3}{2} \right)\cdot (2)$

$b = 3$

The equation of the line in the xz-plane is $z = -\frac{3}{2}\cdot x+3$ or $3\cdot x + 2\cdot z = 6$

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

$a = 3$ , $b = 3$ , $c = 2$ , $d = 6$

Hence, none of the options presented are valid. The plane is represented by $3 \cdot x + 3\cdot y + 2\cdot z = 6$ .

8 0

3 years ago