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svp [43]
3 years ago
5

What is the equation of the line that is parallel to y=2x+8yand goes through point (−4,1)?

Mathematics
1 answer:
vekshin13 years ago
7 0
<span>y=2x+8 slope = 2

</span><span>parallel to y=2x+8, so equation has same slope = 2
</span><span>goes through point (−4,1)
</span>then
y = mx+b
1 = 2(-4) + b
b = 9

so the equation
y = 2x + 9

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Ms Acosta received a job as a teacher with a starting salary of $34,000 according to her contract she will receive a 1.5% increa
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3 years ago
Recall that the owner of a local health food store recently started a new ad campaign to attract more business and wants to know
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The answer to the given problem is provided below.

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8 0
3 years ago
HURRYYY HELP PLZ
snow_tiger [21]
You don't see any y values that are the same, so you have to write the equations first
equation 1: the slope is m=(14-2)/(3-0)=4, and the y intercept is 2 (you can tell from the point (0,2)) so the equation is: y=4x+2

equation 2:
your last pair of x and y are not correct. they must be 3, -3 instead, not 3, 3
the slope is m=[(-3-(-12)]/(3-0)=3, and the y intercept is -12, so the equation is y=3x-12

solve the system of equation: y=4x+2 and y=3x-12
4x+2=3x-12
x=-14
y=3x-12=3*(-14)-12=-54
so the answer is (-14, -54)
7 0
2 years ago
Read 2 more answers
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