There is 9 windows left and to finish installing the rest of the windows it will take 45 hours to finish all of the windows in the building
If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.
So, what are the chances of it not occurring in 1 trip?
1−.37=.63
What about not occurring in 2 trips?
(1−.37)⋅(1−.37)=.63⋅.63=.3969
Now what about not occurring in 4 trips?
.63^4 = 0.15752961
We must subtract this value from 1
(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:
1−0.15752961 = .84247039
TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.
Answer:
2,7
Step-by-step explanation:
Answer:
6%
Step-by-step explanation:
let 't' = tax rate
45t = 2.7
t = 2.7/45
t = .06
Answer:
12, 45, 1.8, -9, 18
Step-by-step explanation:
up up down down left right left right b a start
