The answer is (-2,-4) to solve this you need to add the X’s and divide by 2 and that will be your X for the midpoint, you do the same with the Y’s to find the y for your midpoint
Answer:
Answer is in the attachment.
Step-by-step explanation:
To graph x>2 consider first x=2. x=2 is a vertical line and if you want to graph x>2 you need to shade to the right of the vertical line.
To graph x+y<2, I will solve for y first.
x+y<2
Subtract x on both sides:
y<-x+2
Consider the equation y=-x+2. This is an equation with y-intercept 2 and slope -1 or -1/1. So the line you have in that picture looks good for y=-x+2. Now going back to consider y<-x+2 means we want to shade below the line because we had y<.
Now where you see both shadings will be intersection of the shadings and will actually by your answer to system of inequalities you have. In my picture it is where you have both blue and pink.
I have a graph in the picture that shows the solution.
Also both of your lines will be solid because your question in the picture shows they both have equal signs along with those inequality signs.
Just in case my one graph was confusing, I put a second attachment with just the solution to the system.
For this case we must find an expression equivalent to:
![x ^ 3 * y ^ {- 7}](https://tex.z-dn.net/?f=x%20%5E%203%20%2A%20y%20%5E%20%7B-%207%7D)
By definition of power properties we have to meet:
![a ^ {-1} = \frac {1} {a ^ 1} = \frac {1} {a}](https://tex.z-dn.net/?f=a%20%5E%20%7B-1%7D%20%3D%20%5Cfrac%20%7B1%7D%20%7Ba%20%5E%201%7D%20%3D%20%5Cfrac%20%7B1%7D%20%7Ba%7D)
Then, we can rewrite the expression as:
![x ^ 3 * \frac {1} {y ^ 7} =\\\frac {x ^ 3} {y ^ 7}](https://tex.z-dn.net/?f=x%20%5E%203%20%2A%20%5Cfrac%20%7B1%7D%20%7By%20%5E%207%7D%20%3D%5C%5C%5Cfrac%20%7Bx%20%5E%203%7D%20%7By%20%5E%207%7D)
Answer:
![\frac {x ^ 3} {y ^ 7}](https://tex.z-dn.net/?f=%5Cfrac%20%7Bx%20%5E%203%7D%20%7By%20%5E%207%7D)
Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>