Identify the center and radius of the circle whose equation is (x+2)^2+(y-3)^2=49.
1 answer:
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Given the set of equations:
2x + y = 10
y = 3x
Let's solve for x and y.
Here, let's use substitution method.
Substitute 3x for y in equation 1:
2x + y = 10
2x + 3x = 10
5x = 10
Divide both sides by 5:
In equation 2, substitute 2 for x to find y.
y = 3x
y = 3(2)
y = 6
Therefore, we have:
x = 2 and y = 6
ANSWER:
x = 2, y = 6
At x = 8, y = 4
At x = 14, y = 7
At y = 3, x = 6
Solution:
Given rule:
At x = 8,
Hence at x = 8, y = 4.
At x = 14.
Hence at x = 14, y = 7.
At y = 3
Multiply by 2 on both sides.
Hence at y = 3, x = 6.
The image of the table is attached below.
