Answer:
Option B.
Step-by-step explanation:
Given information:
We need to find 95% confidence interval estimate for the difference between the means of two normally distributed populations.
Formula for confidence interval:
From the standard normal table it is clear that the z value at 95% confidence interval is 1.96.
Substitute the given values in the above formula.
The lower confidence limit is −18.78.
Therefore, the correct option B.
<h3>
Answer: 0.3125</h3>
As a fraction, 0.3125 = 5/16
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Work Shown:
n = 5 trials
p = 0.5 is the probability of landing tails
x = 3 = number of tails we want to happen
Use the binomial PDF formula to get
(n C x)*(p)^x*(1-p)^(n-x)
(5 C 3)*(0.5)^3*(1-0.5)^(5-3)
10*(0.5)^3*(0.5)^(2)
0.3125
note: flipping a single coin 5 times is the same as flipping 5 independent coins one time
Line segments are taken to line segments of the same length;
angles are taken to angles of the same measure; and.
lines are taken to lines and parallel lines are taken to parallel lines.
Hope this helps!
-2x+5y=-10 can be rewritten as
y=2/5x-2
therefore the y intercept is (0,-2) because in the equation y=mx+b, b is the y intercept and -2= b in this equation.
Answer:
0.2297453
Step-by-step explanation:
Given that :
Total faces of = 12 labeled 1 - 12
Probability of showing a 2 ;
P = required outcome / Total possible outcomes
P(showing a 2) = 1 /12
Hence, probability of not showing a 2 ;
P(showing a 2)' = 1 - 1/2 = 11/12
Probability that atleast one of 3 cubes shows a 2 :
1 - P(none of the cubes shows a 2)
P(none of the cubes shows a 2) =
(11/12 * 11/12 * 11/12) = 0.7702546
1 - 0.7702546 = 0.2297453