For the answer to the question above,
1. If we let x as the side of the square cut-out, the formula for the capacity (volume) of the food dish is:
V = (12 - 2x)(8 - 2x)(x)
V = 96x - 40x^2 + 4x^3
To find the zeros, we equate the equation to 0, so, the values of x that would result to zero would be:
x = 0, 6, 4
2. To get the value of x to obtain the maximum capacity, we differentiate the equation, equate it to zero, and solve for x.
dV/dx = 96 - 80x + 12x^2 = 0
x = 5.10, 1.57
The value of x that would give the maximum capacity is x = 1.57
3. If the volume of the box is 12, then the value of x can be solved using:
12 = 96x - 40x^2 + 4x^3
x = 0.13, 6.22, 3.65
The permissible value of x is 0.13 and 3.65
4. Increasing the cutout of the box increases the volume until its dimension reaches 1.57. After that, the value of the volume decreases it reaches 4.
5. V = (q -2x) (p - 2x) (x)
x5 - 10x2 - 8
—————————————
x - 2
Answer:
See the proof.
Step-by-step explanation:
<u>Statement </u><u> </u><u> Reason</u>
1.∠1 and ∠2 are supplementary angles --- Given
2. m∠1 + m∠2 = 180° --- Linear pair, they are supplementary
3. m∠1 and m∠3 are supplementary angles -- m∠1 + m∠3= 180
(Supplementary angles add upto 180 degrees)
4. m∠1 and m∠3 ------ Exterior sides in opposite rays
5. m∠1 + m∠2 = m∠1 + m∠3 ------ Transitive property
6. m∠2 = m∠3 -------------- Subtraction property
7. l || m ------------- If two lines are cut by transversal the alternative interior
angles are the same, then the lines are paralle.
Thank you.
Right angle are known as exactly 90 degrees corresponding to a quarter turn.
Answer:
57.8125% or approx. 57.8%
Step-by-step explanation:
There is a 1/4, or 25%, or 0.25 chance that an egg has salmonella.
Thus, there is a 75%, or 0.75 chance that an egg DOESN'T contain salmonella.
Let's find the probability that all 3 of Larry's eggs are free from salmonella. Larry would have to hit that 75% chance 3 times in a row. The chance of that happening is:
0.75 * 0.75 * 0.75 = 
= 0.421875
From this, we can deduce that if there is a 0.421875 (42.1875%) chance that all eggs are safe to eat, there must be a...
1 - 0.421875 = 0.578125
...0.578125 (57.8125%) chance that 1 or more of Larry's eggs do have salmonella.
Answer: approx. 57.8% or 57.8125%
