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dangina [55]
3 years ago
11

HELP PLEASE DUE AT 10:30 PM I AM VERY LIGHT HEADED!!!!

Mathematics
2 answers:
belka [17]3 years ago
8 0

11) parallelogram
12)kite
13) rhombus
14) trapezium
15) equilateral triangle
16) isosceles

— hope this helps !!
VikaD [51]3 years ago
4 0

Answer:

15 and 16 are acute triangles and 12 is a kite and 13 is a rhombus sorry that is all I know

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2 years ago
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The volume of a cylinder is 256 in height of the cylinder is 1 in. What is the radius of the​ cylinder?
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7 0
2 years ago
what is the value of x in the diagram below? if necessary round your answer to the nearest tenth of a until
VladimirAG [237]

Answer:

C

Step-by-step explanation:

Calculate AC using Pythagoras' identity in ΔABC

AC² = 20² - 12² = 400 - 144 = 256, hence

AC = \sqrt{256} = 16

Now find AD² from ΔACD and ΔABD

ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²

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Equate both equations for AD², hence

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40x = 288 ( divide both sides by 40 )

x = 7.2 → C



6 0
2 years ago
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