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3 years ago

greg wants to divide a 2 and 1/2 pound block of cheese into four equal pieces. How much will each piece weigh?

Mathematics

1 answer:

Alex73 [517]3 years ago

5 0

let's firstly convert the mixed fraction to improper fraction and then divide.

$\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{5}{2}\div 4\implies \cfrac{5}{2}\div \cfrac{4}{1}\implies \cfrac{5}{2}\cdot \cfrac{1}{4}\implies \cfrac{5}{8}$

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The following data comparing wait times at two rides at Disney are listed below: Position Pirates Splash Mountain Sample Size 32

myrzilka [38]

Answer:

a) $(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

b) $t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

Step-by-step explanation:

Data given and notation

$\bar X_{A}=14.68$ represent the mean for Pirates

$\bar X_{B}=18.77$ represent the mean for Splash Mountain

$s_{A}=11.87$ represent the sample standard deviation for the sample Pirates

$s_{B}=16.79$ represent the sample standard deviation for the sample Slpash Mountain

$n_{A}=32$ sample size selected for Pirates

$n_{B}=30$ sample size selected for Splash Mountain

$\alpha=0.02$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a

The confidence interval would be given by:

$(\bar X_A -\bar X_B) \pm t_{\alpha/2} \sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}$

The degrees of freedom are given by:

$df = n_A +n_B -2 = 32+30-2 = 60$

Since we want 98% of confidence the significance level is $\alpha =1-0.98 =0.02$ and $\alpha/2 =0.01$ , we can find in the t distribution with df =60 a critical value that accumulates 0.01 of the area on each tail and we got:

$t_{\alpha/2}= 2.39$

And replacing we got for the confidence interval:

$(14.68 -18.77) - 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =-12.968$

$(14.68 -18.77) + 2.39 \sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}} =4.788$

Part b

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the means are equal, the system of hypothesis would be:

Null hypothesis: $\mu_{A} = \mu_{B}$

Alternative hypothesis: $\mu_{A} \neq \mu_{B}$

the statistic is given by:

$t=\frac{\bar X_{A}-\bar X_{B}}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{14.68-18.77}{\sqrt{\frac{11.87^2}{32}+\frac{16.79^2}{30}}}}=-1.10$

6 0

3 years ago

Daniel, Clarence, and Matthew split a $20.20 dinner bill so that Daniel pays half of what

Bingel [31]

Answer:

8.80$

Step-by-step explanation:

Total 20.20. 6.06 x 2=12.12. 20.20-12.12=8.80$

Mathew paid 8.80$

Clarence paid 12.12$

Daniel paid 6.06$

7 0

3 years ago

Grace rolls a fair, 6-sided die 50 times.

Lostsunrise [7]

Answer:

Step-by-step explanation:

Here's the thing. It is easier to figure out the probability of not getting a six even once during the 50 rolls.

The chance of that happening is (5/6)^50 = 0.00010988

So the probability is succeeding is (1 - 0.00010988) = 0.9999 rounded to 4 places.

5 0

3 years ago

Can anyone help me???

Alenkinab [10]

Answer: think A

Step-by-step explanation:

3 0

3 years ago

Can someone help me find the annulus of the shaded area? much appreciated

Dimas [21]

Answer:

34.83

Step-by-step explanation:

7 0

3 years ago