Answer:

Step-by-step explanation:
The change of form formula (exponential to logarithm) is:

Looking at the problem given, we can simply write the logarithmic form as:

This is the answer.
=> 50 x 100 = 5000
<span>Expression of calculator’s display for this given number:
0.00000000000096
How to get this answer.
Since it’s a decimal number, I am pretty sure that the number will be negative.
Now, let’s move the decimal points to the right.
=> Thus the answer is c. 9.6e-13
Because, from the decimal point, we move to the right 13 times, and since it’s
decimal, it’s negative. So the answer is 9.6e – 13
e represents to the number of zeros.</span>
Answer:
C.
D.
E.
Step-by-step explanation:
Formula for volume of a cuboid
. where l is the length, w is the width and h is the height.
Using this equation we can answer the question by using the values given.

From the list of answers, we can compare each one to the answer we got and see if they match up.
The answers that match up are:
C.
- it is exactly like the answer we got.
D.
- if we simplify the brackets, it is exactly like the answer we got.
E.
- once again, if we simplify the brackets it is like the answer we got.
None of the other answers are correct as they do not match up with the answer we got.
<span><u><em>The correct answer is: </em></u>
D) neither the relation (length, volume) nor the relation (volume, length) is a function.
<u><em>Explanation: </em></u>
A function is a relation in which each element of the domain is mapped to no more than <u>1 element</u> of the range.
For (length, volume), the domain would be length and the range would be volume.
There could possibly be a length value that is mapped to more than one volume value, depending on the height of the pool. This means that (length, volume) is not always a function.
For (volume, length), volume is the domain and length is the range.
There could possibly be a volume that is mapped to more than one length, depending on the height of the pool. This means that (volume, length) is not always a function either.</span>