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Paraphin [41]
3 years ago
5

The covariance between the returns on two assets is negative. This occurs when Group of answer choices

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

Step-by-step explanation:

The covariance between the returns on two assets is negative .this occurs when group of answer choice

Answer:

on average the return on one asset increases while the return on the other assets decreases.

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UW= 2 and UX=y. Write an expression for WX
Eddi Din [679]
Divide each term by U and simplify. X=y/U and W=2/U. Next, solve the equation for y. Simplify the left side then cancel the common factor of U. 1/1*y/1=y

W=2/U. Multiply 1/1*y/1=y/1 so, y/1=y and W=2/U. Next, divide y/y to get 1 now y=y, still W=2/U. Now, move all terms containing y to the left side.  Since, Y contains the variable to solve for, move it to the left side of the equation by subtracting y from both sides. Now, y-y=0 still W=2/U.  Next, subtract y from y to get zero and still W=2/U.  Subtract y from y to get zero or 0=0 and W=2/U is your expression since 0=0.


Next: UW=m and WX=y+14  write expression for UX

First, divide each term by W and simplify. U=m/W, WX=y+14. Next, solve the equation for Y. Move y from the right side of the equation to the left side. Still, U=m/W and y=-14+WX.  We must reorder -14 and WX. U=m/w and y=WX-14.
Replace the variable U with m/W in the expression to (m/W)X. Next, simplify (m/W)X. Now, write X and a fraction with denominator 1. Looks like this
fractions are side by side m/W X/1 . Multiply, m/W and X/1 to get mX/W.
mX/W is your final expression for UW=m and WX=y+14 expression for UX.
8 0
4 years ago
Is this right from greatest to least or do I have to change anything???
Alinara [238K]

Answer:

Yes its correct

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A school has two varsity basketball teams. One is the girls' team, and the other is the boys' team. On any given Saturday in Dec
belka [17]

The probability that either the girls' or boys' team gets a game is 0.85            

Step-by-step explanation:

Step 1:

Let P(G) represent the probability of girls team getting a game and P(B) represent the probability of the boys team getting a game.

P(B ∪ G) represents the probability of either girls and boys team getting a game.

P(B ∩ G) represents the probability of both girls and boys team getting a game.

Step 2:

It is given that P(G) = 0.8, P(B) = 0.7 and P(B ∩ G) = 0.65

We need to find the probability of either girls or boys team getting a game which is represented by P(B ∪ G)

Step 3:

P(B ∪ G) = P(B) + P(G) - P(B ∩ G)

= 0.8 + 0.7 - 0.65 = 0.85

Step 4:

Answer:

The probability that either the girls' or boys' team gets a game is 0.85

5 0
4 years ago
5. A family spends T 600.00 a day for food which is 40% of the
BabaBlast [244]

Answer:

<h3>15%</h3>

Step-by-step explanation:

<h3>First , We will solve their daily Income </h3>

• Income = spends / rate

• Income = 600 / 40%

• Income = 600 / 0 .40%

• Income = 1500

Thus , Their daily Income is 1500 . Now ,We will solve for the rate of the Allowance .

• Rate = spent / Income

• Rate = 225 / 1500

• Rate = 0.15

• Rate = 15%

Therefore, the percent of the family's daily Income of the Allowance of their children's is 15%

<h3>Hope this helps you XD ✌️</h3><h2>Carry on learning !! </h2>

4 0
2 years ago
Find the second derivative y=1/5x^2+1/11x
Amiraneli [1.4K]

\frac{dy}{dx}=\frac{1}{5}.x^{2-1}.2 + \frac{1}{11}.x^{1-1}.1

\frac{dy}{dx}=\frac{2}{5}.x+\frac{1}{11}

\frac{d^2y}{dx^2}=\frac{2}{5}.x^{1-1}.1

\frac{d^2y}{dx^2}=\frac{2}{5}

8 0
3 years ago
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