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3 years ago

Given f(x)=4x2−5 and g(x)=x+3 . What is (fg)(x) ?

Mathematics

2 answers:

kozerog [31]3 years ago

7 0

I just took the test, it was A. 4x^3+12x^2-5x-15 :)

vova2212 [387]3 years ago

7 0

Answer:

$(fg)(x)=4x^3+12x^2-5x-15$

First option is correct.

Step-by-step explanation:

We have been given that

$f(x)=4x^2-5$

$g(x)=x+3$

We know that $(fg)(x)=f(x)g(x)$

Hence, we have to find the product of f(x) and g(x)

$(fg)(x)=(4x^2-5)(x+3)$

Apply distributive property

$(fg)(x)=4x^2\cdot x+4x^2\cdot3-5x-5\cdot3$

Simplifying, we get

$(fg)(x)=4x^3+12x^2-5x-15$

First option is correct.

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The length of a rectangle is twice its width. Given the length of the diagonal is $5\sqrt{5}$, find the area of the rectangle.

lianna [129]

Answer: Area of rectangle is 50 square units.

Step-by-step explanation:

Since we have given that

Diagonal of the rectangle = 5√5

Let the width of rectangle be 'x'

Let the length of rectangle be '2x'

As we know the formula for diagonal of rectangle:

$5\sqrt{5}=\sqrt{l^2+w^2}\\\\(5\sqrt{5}})^2=(2x)^2+x^2\\\\125=4x^2+x62\\\\125=5x^2\\\\\dfrac{125}{5}=x^2\\\\25=x^2\\\\x=\sqrt{25}\\\\x=5\ units$

So, Length of rectangle be 2x=2×5=10 units

And the area of the rectangle is given by

$Area=Length\times width\\\\Area=10\times 5\\\\Area=50\ sq.\ unit$

Hence, area of rectangle is 50 square units.

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2 years ago

ASAAPPPPPP!!!!! Complete the tables of values

velikii [3]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$ and $a^{0}$ = 1

Substitute the values of x into $4^{-x}$

x = 0 → $4^{0}$ = 1 ⇒ a = 1

x = 2 → $4^{-2}$ = $\frac{1}{4^{2} }$ = $\frac{1}{16}$ , hence

b = $\frac{1}{16}$

x = 4 → $4^{-4}$ = $\frac{1}{4^{4} }$ = $\frac{1}{256}$ , hence

c = $\frac{1}{256}$

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3 years ago

alukav5142 [94]

Most appropriate answer is
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Answer:

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Step-by-step explanation:

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