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3 years ago

Which of the following pairs is not correctly written in scientific notation?

Mathematics

1 answer:

topjm [15]3 years ago

4 0

The second pair. It should be 6.5 x 10 to the third power, not the second

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If sin θ = 1 over 3 and tan θ < 0, what is the value of cos θ?

alexira [117]

Answer:

2√2 / 3 (first answer choice)

Step-by-step explanation:

If tan Ф < 0, then Ф must be in either Quadrant II or Quadrant IV.

If sin Ф = +1/3, then Ф (for this problem) is in Quadrant II.

Remembering that sin Ф = opp / hyp = 1 / 3, we use the Pythagorean Theorem to find the adj side:

adj² + 1² = 3², or

adj² + 1 = 9, or adj² = 8. Since Ф is in Quadrant II, adj is negative.

The value of cos Ф = adj / hyp = √8 / 3 = 2√2 / 3

3 0

2 years ago

HELPPP <br> If Julie makes $20,000 a year, how much will she make in a day?

NNADVOKAT [17]

I’m not sure I would help you if knew

7 0

2 years ago

Someone pls help...<br> I'm terrified I'm gonna fail and this test is literally my life...

guajiro [1.7K]

Answer: it is 49 or -49

Step-by-step explanation:

if you divide 49 by 7 it comes out to seven because 7 times 7 is 49.

6 0

3 years ago

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$

Hence, the required number of ways =27434

5 0

2 years ago

Solve the equation. 2x squared-3x+1=0

natali 33 [55]

$2x^2-3x+1=0\\\\2x^2-2x-x+1=0\\\\2x(x-1)-1(x-1)=0\\\\(x-1)(2x-1)=0\iff x-1=0\ \vee\ 2x-1=0\ \ \ \ |+1\\\\x=1\ \vee\ 2x=1\ \ \ |:2\\\\\boxed{x=1\ \vee\ x=0.5}$

4 0

3 years ago